Question

1. As a particle moves 12m along an electric field of strength 76N/C, its electrical potential energy decreases by 4.9 * 10 ^ - 16 * J . What is the particle's charge?

Answer 1

Answer:

Charge, $q=5.37\times 10^{-19}\ C$

Explanation:

Given that,

Distance moved by particle, d = 12 m

Electric field strength, E = 76 N/C

Decrease in potential energy, $P=4.9\times 10^{-16}\ J$

We need to fine the charge on the particle. The change in potential energy of the system is given by :

$P=qEd$

q is charge

$q=\dfrac{P}{Ed}\\\\q=\dfrac{4.9\times 10^{-16}}{76\times 12}\\\\q=5.37\times 10^{-19}\ C$

So, the charge on the particle is $5.37\times 10^{-19}\ C$.