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shusha [124]
3 years ago
10

Easy Physics question plz help ASAP

Physics
1 answer:
Aleks04 [339]3 years ago
5 0

Answer:

B___________________________________________:)

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Technician A says that gears may be used to apply torque to other rotating parts. Technician B says that gears may be used to mu
Goryan [66]

Answer:

Both technicians are right.

Explanation:

Torque is defined as a rotational force that can be calculated by the formula T= F.d. Being F the force applied to a body to make it rotate and d the distance since the force is applied.  

T= F . d

So technician A is saying that gear can apply a torque to another gear, and that is true because it’s applying a rotational force to the gear next to it, in simple terms  -anytime I make something rotate, I'm generating a torque-. And for technician B, the torque also can vary as a function of the distance of the force applied (size of the gear), so, it can multiply the torque and change the rotation speed.

5 0
4 years ago
A bottle of soda always has a space between the cape and the top of the liquid. Explain<br>​
serious [3.7K]

Answer:

All soft drinks contain water. When soft drink bottles are chilled in sub-zero temperatures, the water on account of its anomalous expansion expands. Thus, to provide space for expanding water, soft drink bottles are not completely filled as otherwise they will burst.

Explanation:

6 0
3 years ago
Read 2 more answers
Two long, parallel wires are separated by a distance of 3.20 cm. The force per unit length that each wire exerts on the other is
AURORKA [14]

Answer:

(a)The current in the second wire = 9.43 A

(b) The two current are in the opposite direction.

Explanation:

The force per unit length (F/l) on a current carrying conductor = μ₀I₁I₂/2πr

Making I₂ The subject of the equation,

I₂ = [2πr(F/l)]/μ₀I₁.................... Equation 1

Where I₁ = Current in the first wire, I₂ = current in the second wire, μ₀ = permeability of vacuum, r = distance of separation between the two wires.

<em>Given: F/l = 3.30 × 10⁻⁵ N/m, I₁ = 0.56 A, r = 3.20 cm = 0.032 m.</em>

<em>Constant: </em>μ₀= 4π × 10⁻⁷ Am⁻¹.

Substituting these values into equation 1

I₂ = (2π × 0.032 × <em>3.30 × 10⁻⁵ )/(</em>4π × 10⁻⁷×0.56)

I₂ = (0.032 × 3.3 × 100)/1.12

I₂ = 10.56/1.12

I₂ = 9.43 A

Therefore the current in the second wire = 9.43 A

(b) The two current are in the opposite direction, because the force on each wire repel each other.

7 0
3 years ago
By what factor is the intensity of sound at a rock concert louder than that of a whisper when the two intensity levels are 120 d
lyudmila [28]

Answer:

d) 7.94\times 10^{9}

Explanation:

β₁ = sound level of sound at rock concert = 120 dB

β₂ = sound level of sound due to whisper = 21 dB

I₁ = Intensity of sound at rock concert

I₂ = Intensity of sound due to whisper

sound level of sound at rock concert is given as

\beta _{1} = 10 log\left ( \frac{I_{1}}{10^{-12}} \right )

120 = 10 log\left ( \frac{I_{1}}{10^{-12}} \right )

12 = log\left ( \frac{I_{1}}{10^{-12}} \right )               Eq-1

sound level due to whisper is given as

\beta _{2} = 10 log\left ( \frac{I_{2}}{10^{-12}} \right )

21 = 10 log\left ( \frac{I_{2}}{10^{-12}} \right )

2.1 = log\left ( \frac{I_{2}}{10^{-12}} \right )                          Eq-2

subtracting Eq-2 from Eq-1

12 - 2.1 = log\left ( \frac{I_{1}}{10^{-12}} \right ) - log\left ( \frac{I_{2}}{10^{-12}} \right )

9.9 = log\left ( \frac{I_{1}}{I_{2}} \right )

\left ( \frac{I_{1}}{I_{2}} \right ) = 7.94\times 10^{9}

6 0
3 years ago
What is the KE of a 27 kg mass moving at 3m/s?
Naily [24]

Answer:

121.5 J

Explanation:

3 0
3 years ago
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