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Nookie1986 [14]
3 years ago
15

The water level in a tank is 20 m above the ground. a hose is connected to the bottom of the tank, and the nozzle at the end of

the hose is pointed straight up. the tank is at sea level, and the water surface is open to the atmosphere. in the line leading from the tank to the nozzle is a pump, which increases the pressure of water. if the water jet rises to a height of 30 m from the ground, determine the minimum pressure rise supplied by the pump to the water line. take the density of water to be rho = 1000 kg/m3.
Physics
1 answer:
Damm [24]3 years ago
5 0

Answer:

P_(pump) = 98,000 Pa

Explanation:

We are given;

h2 = 30m

h1 = 20m

Density; ρ = 1000 kg/m³

First of all, we know that the sum of the pressures in the tank and the pump is equal to that of the Nozzle,

Thus, it can be expressed as;

P_(tank)+ P_(pump) = P_(nozzle)

Now, the pressure would be given by;

P = ρgh

So,

ρgh_1 + P_(pump) = ρgh_2

Thus,

P_(pump) = ρg(h_2 - h_1)

Plugging in the relevant values to obtain;

P_(pump) = 1000•9.8(30 - 20)

P_(pump) = 98,000 Pa

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milligrams

Explanation:

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This is about; a thousandth of a gram.

  A grain of salt is a very small particle size that can still be visible with the eye.

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For substances like this, we use the milligram:

             1000milligram  = 1g

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A particle moving with initial velocity of 5m/s is subjected to a uniform acceleration of -2.5 m/s2.find the displacement for ne
LUCKY_DIMON [66]
1/2vt^2-1/2at^2
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6 0
2 years ago
If jack was traveling north 120 miles and it took him 3 hours to get there. what is the velocity that jack was traveling? is thi
Dimas [21]

Answers:

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4 0
3 years ago
A harmonic wave on a string with a mass per unit length of 0.050 kg/m and a tension of 60 N has an amplitude of 5.0 cm. Each sec
Dennis_Churaev [7]

Answer:

Power of the string wave will be equal to 5.464 watt

Explanation:

We have given mass per unit length is 0.050 kg/m

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Amplitude of the wave A = 5 cm = 0.05 m

Frequency f = 8 Hz

So angular frequency \omega =2\pi f=2\times 3.14\times 8=50.24rad/sec

Velocity of the string wave is equal to v=\sqrt{\frac{T}{\mu }}=\sqrt{\frac{60}{0.050}}=34.641m/sec

Power of wave propagation is equal to P=\frac{1}{2}\mu \omega ^2vA^2=\frac{1}{2}\times 0.050\times 50.24^2\times 34.641\times 0.05^2=5.464watt

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6 0
3 years ago
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irakobra [83]

Answer:

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Explanation:

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Because of this, the answer is that according to signal detection theory, the ability to detect a stimulus depends not only on the intensity of the stimulus but also on other variables such as the level of noise in the system and your expectations.

8 0
3 years ago
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