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Lerok [7]
3 years ago
7

What can a machine do?

Physics
2 answers:
zlopas [31]3 years ago
3 0

Answer:

B. Make the work you do feel easier

statuscvo [17]3 years ago
3 0

Answer:

Something a machine can do is Decrease the work needed to do something and a machine can also do make the work you do easier.

Explanation:

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A frictionless pendulum of length of 3 m swings with an amplitude of 10o. At its maximum displacement, the potential energy of t
olchik [2.2K]
<h2>Option A is the correct answer.</h2>

Explanation:

For a simple pendulum we have at any position

             Total energy = Constant        

             Kinetic energy + Potential energy = Constant

At maximum displacement of pendulum, velocity is zero, hence kinetic energy is zero.

At maximum displacement the pendulum only have potential energy.

Given that maximum potential energy is 10 J.

 That is at any position                

                     Kinetic energy + Potential energy = 10 J

Now we need to find kinetic energy when potential energy is 5 J.

                     Kinetic energy + 5 J = 10 J

                     Kinetic energy = 5 J

Option A is the correct answer.

6 0
3 years ago
Please help ill give brainliest.
oee [108]
The answer is the last option "Respiration" 
3 0
3 years ago
Read 2 more answers
What are the advantages of having a roof with a lower thermal conductivity?
Paul [167]

Answer:

less energy is needed to heat the house

the roof is a better insulator

8 0
3 years ago
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A solid conducting sphere with radius 0.75 m carries a net charge of 0.13 nC. What is the magnitude of the electric field at a p
Delicious77 [7]

Answer:

Explanation:

given that

Radius =0.75m

Cnet=0.13nC

a. Electric field inside the sphere located 0.5m from the center of the sphere.

The electric field located inside the sphere is zero.

b. The electric field located 0.25m beneath the sphere.

Since the radius is 0.75m

Then, the total distance of the electric field from the centre of the circle is 0.75+0.25=1m

Then

E=kq/r2

K=9e9Nm2/C2

q=0.13e-9C

r=1m

Then,

E= 9e9×0.13e-9/1^2

E=1.17N/C. Q.E.D

3 0
3 years ago
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Where do most stars fall on the Hertzsprung-Russell diagram?
Alex_Xolod [135]

Answer:

Most of the stars occupy the region in the diagram along the line called the main sequence. During the stage of their lives in which stars are found on the main sequence line, they are fusing hydrogen in their cores.

7 0
3 years ago
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