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2 years ago

What can a machine do?

Physics

2 answers:

zlopas [31]2 years ago

3 0

Answer:

B. Make the work you do feel easier

statuscvo [17]2 years ago

3 0

Answer:

Something a machine can do is Decrease the work needed to do something and a machine can also do make the work you do easier.

Explanation:

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NASA is designing a mission to explore Titan, the largest moon of Saturn. Titan has numerous hydrocarbon lakes containing a mix

Vitek1552 [10]

Answer:

Total pressure in atmosphere IS 4.36 atm

Explanation:

Given Data:

Depth of lake is 400 mtr

surface tension is 147 kilopascals

surface temperature 94 kelvin

Gravity = 1.35 m/s^2

specific gravity of methane(liquid) = 0.415

specific gravity of ethane(liquid) = 0.546

density of methane can be obtained as

$\rho_{methane} = 0.415\times 1000 = 415 kg/m^3$

Density of ethane can be obtained as

$\rho_{ethane} = 0.546\times 1000 = 546 kg/m^3$

Total pressure in atmosphere can be obtained as

$P = surface\ tension + \rho_{max}gh$

$= 147 +546\times 1.35\times 400\times 10^{-3}$

= 441.84 kPa

$= 441.84\times 0.009869 atm\kPa$

= 4.36 atm

7 0

2 years ago

26. The equation E=hf describes the energy of each photon in a beam of light. If Planck’s constant, h, were larger, would photon

Elenna [48]

The equation of the energy of a photon is E=h*f.

If we increase the Planck's constant h, the energy would increase.

For example, lets double the value of Planck's constant and name it H:

H=2*h. Now lets put that into the equation for energy that we will call E₂:

E₂=H*f=2*h*f=2*E.

So we can clearly see that E₂=2*E or that if we double Planck's constant, the energy also doubles.

6 0

3 years ago

A playground merry-go-round has a mass of 115 kg and a radius of 2.50 m and it is rotating with an angular velocity of 0.520 rev

tatuchka [14]

Answer:

$W_f = 2.319 rad/s$

Explanation:

For answer this we will use the law of the conservation of the angular momentum.

$L_i = L_f$

so:

$I_mW_m = I_sW_f$

where $I_m$ is the moment of inertia of the merry-go-round, $W_m$ is the initial angular velocity of the merry-go-round, $I_s$ is the moment of inertia of the merry-go-round and the child together and $W_f$ is the final angular velocity.

First, we will find the moment of inertia of the merry-go-round using:

I = $\frac{1}{2}M_mR^2$

I = $\frac{1}{2}(115 kg)(2.5m)^2$

I = 359.375 kg*m^2

Where $M_m$ is the mass and R is the radio of the merry-go-round

Second, we will change the initial angular velocity to rad/s as:

W = 0.520*2 $\pi$ rad/s

W = 3.2672 rad/s

Third, we will find the moment of inertia of both after the collision:

$I_s = \frac{1}{2}M_mR^2+mR^2$

$I_s = \frac{1}{2}(115kg)(2.5m)^2+(23.5kg)(2.5m)^2$

$I_s = 506.25kg*m^2$

Finally we replace all the data:

$(359.375)(3.2672) = (506.25)W_f$

Solving for $W_f$ :

$W_f = 2.319 rad/s$

7 0

3 years ago

The amount of kinetic energy an object has depends upon which of the following factors? I. the object's velocity II. the object'

harina [27]

1.) The object's Velocity

Faster it goes, more kinetic energy it has

8 0

3 years ago

Use each of the following terms in a separate sentence: tissue<br> organ,and function

Andru [333]

"The organ proved to be a vital part of the body's metabolism" "The tissue was damaged from the scalpel but would heal" "The function of the heart is to pump blood"

3 0

3 years ago