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3 years ago

6

A particle oscillates in simple harmonic motion, with amplitude A and period T. The particle starts from position x = A. What is

the magnitude of the particle's displacement a time 3T/2?
A. 3A
B. 6A
C. 2A
D. 0

1 answer:

frozen [14]3 years ago

8 0

Answer:

i guess it is D because,

y = A sin(wt)

w = $\frac{2\pi }{T}$ and t = 3T/ 2

now, Y = A sin ( $\frac{2\pi }{T} X \frac{3T}{2}$ )

so, Y = 0radian

Explanation:

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To understand the direction, let's use the right-hand rule:
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