A particle oscillates in simple harmonic motion, with amplitude A and period T. The particle starts from position x = A. What is
the magnitude of the particle's displacement a time 3T/2?
A. 3A
B. 6A
C. 2A
D. 0
1 answer:
Answer:
i guess it is D because,
y = A sin(wt)
w = 
and t = 3T/ 2
now, Y = A sin ( 
)
so, Y = 0radian
Explanation:
You might be interested in
D make one revolution around the sun hope this helps
<h3>Option D) The red liquid has a smaller specific heat</h3>
When a substance has smaller specific heat it needs less heat to shows changes in it hence making the option D correct.
Answer:
120,000
Explanation:
Millimeters to meters calculation-
Multiply by 1,000.
120 x 1,000 = 120,000.
This is the correct answer and formula.
Hope this helps!
The reactants are on the left and the products are on the right of the equation
Answer:
Explanation:
The path length difference = extra distance traveled
The destructive interference condition is:
where m =0,1, 2,3........
So, ←
![\Delta d = (m+1/2)\lamb da9/tex]so [tex]\Delta d = \frac{\lambda}{2}](https://tex.z-dn.net/?f=%5CDelta%20d%20%3D%20%28m%2B1%2F2%29%5Clamb%20da9%2Ftex%5D%3C%2Fstrong%3E%3C%2Fp%3E%3Cp%3E%3Cstrong%3Eso%20%3C%2Fstrong%3E%5Btex%5D%5CDelta%20d%20%3D%20%5Cfrac%7B%5Clambda%7D%7B2%7D)
⇒ λ = 2Δd = 2×10 = 20
