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lord [1]
3 years ago
6

A particle oscillates in simple harmonic motion, with amplitude A and period T. The particle starts from position x = A. What is

the magnitude of the particle's displacement a time 3T/2?
A. 3A
B. 6A
C. 2A
D. 0
Physics
1 answer:
frozen [14]3 years ago
8 0

Answer:

i guess it is D because,

y = A sin(wt)

w = \frac{2\pi }{T} and t = 3T/ 2

now, Y = A sin ( \frac{2\pi }{T} X \frac{3T}{2})

so, Y = 0radian

Explanation:

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a 75-kg refrigerator is located on the 70th floor of a skyscraper (300 meters above ground). what is the potential energy of the
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Here, you can calculate it's potential energy with respect to ground.
We know, U = mgh
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The acceleration of one of those bugs is equal to 305mi/s.

<h3>Acceleration calculation</h3>

To calculate the insect's acceleration, the action and reaction force of the impact must be considered.

As the insect will hit the helmet, the force it hits is the same force it receives, so we can make the following expression:

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Learn more about acceleration calculation: brainly.com/question/390784

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