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2 years ago

PLZ help Asap!!!!!! I WILL GIVE BRAINLIEST!!!

Chemistry

1 answer:

Sergeu [11.5K]2 years ago

6 0

Answer: Chosen landforms are:

1) Hill

2) Mountain

3) Plateau

4) Valley

Explanation:

1) Hill is an elevated location smaller than a mountain. Location: Land

2) Mountain is a large mass of earth and rock, rising above the common level of the earth or adjacent land, usually given by geographers as above 1000 feet in height (or 304.8 metres).

Location: Land or Water

3) Plateau is a largely level expanse of land at a high elevation. It is also known as tableland.

Location: Land

4) Valley is an elongated depression between hills or mountains, often with a river flowing through it.

Location: Land or Water

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ILL GIVE BRAINLIST IF YOU GET IT RIGHT Which of the following is an example of gravitational potential energy?

FinnZ [79.3K]

A glass jar sitting on a shelf.

If the shelf gets tipped the jar will slide off and convert to kinetic energy as gravity pulls it to land on the next level/floor

6 0

2 years ago

Before any reaction occurs, the concentration of A in the reaction below is 0.0510 M. What is the equilibrium constant if the co

Lilit [14]

Answer:

0.0119

Explanation:

There was a part missing. I think this is the whole question:

Before any reaction occurs, the concentration of A in the reaction below is 0.0510 M. What is the equilibrium constant if the concentration of A at equilibrium is 0.0153 M?

A (aq) ⇌ 2B (aq) + C(aq)

Remember to use correct significant figures in your answer. Do not include units in your response.

First, we have to make an ICE Chart, which stands for initial, change and equilibrium. We will call "x" unknown concentrations.

A (aq) ⇌ 2B (aq) + C (aq)

I 0.0510 0 0

C -x +2x +x

E 0.0510-x 2x x

Since the concentration at equilibrium of A is 0.0153 M, we get

$0.0510 - x = 0.0153 \\x = 0.0357$

We can use the value of x to calculate the concentrations at equilibrium.

$[A]e = 0.0153 M \\[B]e = 2x = 2(0.0357) = 0.0714 M \\[C]e = x = 0.0357 M \\$

The equilibrium constant, Kc, is the ratio of the equilibrium concentrations of products over the equilibrium concentrations of reactants each raised to the power of their stoichiometric coefficients.

$Kc = \frac{[B]^{2} \times [C]}{[A]} = \frac{0.0714^{2} \times 0.0357}{0.0153} = 0.0119$

The equilibrium constant for this reaction at equilibrium is 0.0119.

You can learn more about equilibrium here: brainly.com/question/4289021

7 0

2 years ago

Read 2 more answers

The method used in this experiment is sometimes called the vapor density method. The ideal gas equation can be rearranged to sol

TiliK225 [7]

The correct answer for the question that is being presented above is this one: "B) Temperature."
Here are the following choices:

A) all of these measurements are needed

B) Temperature

C) Molar Mass

D) Pressure

E) Mass

6 0

2 years ago

Anyone know this????

Anastasy [175]

The correct answer is the first one

3 0

3 years ago

What would 12.47 rounded to 2 sig figs be?

Vaselesa [24]

Answer:

Explanation:

To get to this answer you have to look at the number first. So the given number is 12.47 and you need 2 sig figs.

To help you understand this more start off by underlining the first 2 numbers because 2 sig figs are needed. 12.47

Now you want to look at the number after the underlined (I bolded that number). 12.47

If the number is above 5 then you would round the previous number up by one but in this case it is 4 so you do not increase the number. Hence, you getting 12 as your final answer.

Hope this helped! Let me know if you have any questions.

7 0

2 years ago