Answer:
The sample of lead has a volume of 11.1 cm³
Explanation:
<u>Step 1:</u> Data given
x cm³ lead has a density of 11.3 g/cm³
it has the same mass as 330cm³ of a piece of redwood with density 0.38g/cm³
<u>Step 2</u>: Calculate mass of the piece of redwood
Density = mass/volume
mass = density * volume
Mass of the piece of redwood = 0.38 g/cm³ * 330cm³ = 125.4 grams
Since the sample of lead has the same mass, it also has a mass of 125.4 grams
<u>Step 3</u>: Calculate volume of the lead
Density = mass/ volume
Volume = mass/ density
Volume of lead = 125.4g / 11.3g/cm³ = 11.097 cm³≈11.1 cm³
The sample of lead has a volume of 11.1 cm³
Answer:
B.
Explanation:
Most metals can be drawn into a wire while nonmetals would break apart.
Answer:
doublet
Explanation:
Proton MNR is used for the determination of no. of equivalents protons in a molecule
In the molecule, single NMR signal is produced for each set of protons.
Signal splitting is called spin-spin coupling and the splitting of signals depends upon the no. of neighboring proton.
The no. of signal for a proton is equal to n+1, where n is neighboring protons.
In 1-bromo-2-methylpropane, neighboring proton for both methyl protons are one. But the chemical environment of both the methyl protons are different.
Neighboring proton for methyl protons = 1
No. of signal for methyl protons = 1+1 =2
Hence, two doublets will be generated for each set of methyl protons. protons.
Answer:
Metallic bonding
Explanation:
Metals have low ionization energies. Therefore, their valence electrons are easily delocalized (attracted to the neighbouring metal atoms). These delocalized electrons are then not associated with a specific metal atom. Since the electrons are “free”, the metal atoms have become cations, and the electrons are free to move throughout the whole crystalline structure.
We say that a metal consists of an array of cations immersed in a sea of electrons
.
The electrons act as a “glue” holding the cations together.
Metallic bonds are the attractive forces between the metal cations and the sea of electrons.
In an NaK alloy, for example, the Na and K atoms contribute their valence electrons to the "sea". The atoms aren’t bonded to each other, but they are held in place by the metallic bonding.