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My name is Ann [436]
3 years ago
7

PLZ help Asap!!!!!! I WILL GIVE BRAINLIEST!!!

Chemistry
1 answer:
Sergeu [11.5K]3 years ago
6 0

Answer: Chosen landforms are:

1) Hill

2) Mountain

3) Plateau

4) Valley

Explanation:

1) Hill is an elevated location smaller than a mountain. Location: Land

2) Mountain is a large mass of earth and rock, rising above the common level of the earth or adjacent land, usually given by geographers as above 1000 feet in height (or 304.8 metres).

Location: Land or Water

3) Plateau is a largely level expanse of land at a high elevation. It is also known as tableland.

Location: Land

4) Valley is an elongated depression between hills or mountains, often with a river flowing through it.

Location: Land or Water

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A. properties which can be observed since it's what you're physically viewing
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What volume is occupied by 35.2 g of carbon tetrachloride if its density is 1.60 g/ml?
ycow [4]

Density is mass divided by volume. Therefore, volume is mass divided by density.

V=\frac{m}{\rho}=\frac{35.2g}{1.60\frac{g}{ml}}=22.0\ ml

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3 years ago
If I had 3.50 x 10 24molecules of Cl2 gas, how many grams is this?
Zinaida [17]

Answer:

412 g Cl₂

General Formulas and Concepts:

<u>Atomic Structure</u>

  • Reading a Periodic Table
  • Moles
  • Avogadro's Number - 6.022 × 10²³ atoms, molecules, formula units, etc.

<u>Stoichiometry</u>

  • Using Dimensional Analysis

Explanation:

<u>Step 1: Define</u>

[Given] 3.50 × 10²⁴ molecules Cl₂

[Solve] grams Cl₂

<u>Step 2: Identify Conversions</u>

Avogadro's Number

[PT] Molar Mass of Cl - 35.45 g/mol

Molar Mass of Cl₂ - 2(35.45) = 70.9 g/mol

<u>Step 3: Convert</u>

  1. [DA] Set up:                                                                                                       \displaystyle 3.50 \cdot 10^{24} \ molecules \ Cl_2(\frac{1 \ mol \ Cl_2}{6.022 \cdot 10^{23} \ molecules \ Cl_2})(\frac{70.9 \ g \ Cl_2}{1 \ mol \ Cl_2})
  2. [DA] Divide/Multiply [Cancel out units]:                                                           \displaystyle 412.072 \ g \ Cl_2

<u>Step 4: Check</u>

<em>Follow sig fig rules and round. We are given 3 sig figs.</em>

412.072 g Cl₂ ≈ 412 g Cl₂

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What do radio waves and gamma rays have in common?
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