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Korvikt [17]
3 years ago
6

This element:

Chemistry
1 answer:
LuckyWell [14K]3 years ago
7 0
If it was in group 11 where both silver and gold is found, with copper as well, then the answer would be gold. It does have a d-orbital shell in its electron configuration and it is the heaviest in its group. It is common knowledge that it is used as a shiny metal for jewelry, which we can see on accessories nowadays.
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The whiye pigment TiO2 is prepared by the reaction of titanium tetrachloride, TiCl4, with water vapor in the gas phase:
omeli [17]

Answer:

\boxed{\text{62.1 kJ}}

Explanation:

The formula for calculating the enthalpy change of a reaction by using the enthalpies of formation of reactants and products is

\Delta_{\text{r}}H^{\circ} = \sum \Delta_{\text{f}} H^{\circ} (\text{products}) - \sum\Delta_{\text{f}}H^{\circ} (\text{reactants})

                          TiCl₄(g) + 2H₂O(g) ⟶ TiO₂(s) + 4HCl(g)

ΔH°f/kJ·mol⁻¹:    -763.2     -241.828     -939.7    -92.307

\begin{array}{rcl}\Delta_{\text{r}}H^{\circ} & = & [-939.7 + 4(-92.307)] - [-763.2 + 2(-241.828)\\& = & [-939.7 - 369.228] - [-763.2 - 483.656]\\& = & -1308.928 + 1246.856\\& = & \mathbf{-62.1}\\\end{array}\\\text{The amount of heat evolved is } \boxed{\textbf{62.1 kJ}}

5 0
3 years ago
HELP WILL GIVE BRAINLIEST!
Lostsunrise [7]

Answer:

cover the taste with sugar add two times the amount your supposed to put in

Explanation:

3 0
3 years ago
Why is the chemical symbol for calcium ca
Assoli18 [71]
You are right, it's CA Calcium, 40.08, Group 2 and Row 4.
6 0
3 years ago
Name an element in the third period (row) of the periodic table with a total of 4 3p electrons
Wittaler [7]

Answer:

sulfur

Explanation:

sulfur has 4p electrons.

phosphorus has 3p electrons.

The question is asking which one has 4

3 0
3 years ago
The heat capacity of water is 1cal degree'g1 (1 calorie per degree centigrade, per gram). You are given 1 gallon of water at 25
sdas [7]

Answer:

The heat needed to boil 1 gallon of water is 81,490.62 Joules.

Explanation:

Q=mc\Delta T

Where:

Q = heat absorbed or heat lost

c = specific heat of substance

m = Mass of the substance  

ΔT = change in temperature of the substance

We have :

Volume of water = V = 1 gal = 4546.09 mL

Density of water , d= 1 g/mL

mass of water = m = d × V = 1g/mL × 4546.09 mL =  4546.09 g

Specific heat of water = c = 1 Cal/g°C

ΔT = 100°C - 25°C = 75 °C

9 (boiling pint of water is 100°C)

Heat absorbed by the water to make it boil:

Q= 4546.09 g\times 1 Cal/g^oC\times 75^oC=340,956.75 Cal

1 calorie = 4.184 J

Q=\frac{340,956.75}{4.184} J = 81,490.62 J

The heat needed to boil 1 gallon of water is 81,490.62 Joules.

5 0
3 years ago
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