Answer:
See photo
Step-by-step explanation:
We can fill out many of these pretty easily. Look at the picture below. (Black numbers represent what information they already gave us)
Now, for the actual math.
If a total of 46 seventh-graders were surveyed and 28 seventh-graders spent more than an hour on their phone, then that means that there would have to be 46-28=18 students that spend less than an hour on their phone.
If there are 43 total students that spend more than an hour on their phone, and 28 of those are seventh-graders, then there are 43-28=15 eighth-graders that spend more than an hour on their phone
Then, if there are 27 total eighth-graders, and 15 of those spend more than an hour, then that leaves 27-15=12 eighth-graders that spend less than an hour on their phone.
Lastly, figure out the total numbers.
There are 18 seventh-graders and 12 eighth-graders that spend less than an hour on their phone, so there is a total of 18+12 = 30 students that spend less than an hour on their phone.
There are a total of 46 seventh-graders and 27 eighth-graders that were surveyed, which is a total of 73 students surveyed.
Answer:
See Explanation
Step-by-step explanation:
This question requires further details. In absence of the details, I will answer on a general term.
When a line is dilated (whether expanded or compressed), the new line will be on the same line with the dilated line; however, the length of both lines will be different
Take for instance:
<em>Line AB of coordinate (1,3) is horizontally dilated by 2, </em>
<em>Horizontal dilation rule is: y = f(cx) where c is the dilation factor</em>
<em />
<em>So, the new point will be </em>
<em>A'B' = (1, 3 * 2)</em>
<em>A'B' = (1,6)</em>
<em />
<em>When you compare the x coordinate of both line, you will observe that they have the same x coordinate of 1. </em>
<em>This implies that they are on the same level but different length</em>
<em />
The same is applicable to vertical dilation
<em />
<em>the new point will be:</em>
<em />
A1 = first term = 4
a2 = second term = a1+5 = 4+5 = 0
a3 = third term a1 + 5 + 5 = a1 + 5(n-1), where n is the subscript that represents which term we're discussing.
an=4+5(n-1).
Is this correct? Let's check it and find out.
What is your prediction for a2? Here, n = 2. Then a2 = 4+5(2-1), or 4+5, or 9. That agrees with the given sequence rule.
Thus, the 250th term would be 4+5(250-1). Evaluate this, please.