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faust18 [17]
3 years ago
11

Tripling the displacement from equilibrium of an object in simple harmonic motion will bring about a change in the magnitude of

the object's acceleration by what factor?
Physics
1 answer:
Anni [7]3 years ago
7 0

Answer:

acceleration will be tripled.

Explanation:

We know, when an object is performing Simple harmonic motion, the force

experience by it is directly proportional to its displacement from its mean position.

Also, F = ma , therefore, acceleration is also proportional to its displacement .

Now, F = kx

Therefore, a=\dfrac{k\ x}{m}

If we triple the displacement i.e, 3x.

Acceleration a'=\dfrac{k(3x)}{m}=3a.

Therefore, acceleration is also tripled.

Hence, this is the required solution.

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A flask is filled with 1.57 L (L: liter) of a liquid at 90.6 °C. When the liquid is cooled to 10.2 °C, its volume is only 1.38 L
nydimaria [60]

The coefficient of volume expansion of the liquid = 1.97 × 10⁻³ /⁰C

<h3>What is the coefficient of volume expansion of the liquid?</h3>

The amount of volume that a substance expands by per unit of its original volume for each degree that its temperature rises is known as the coefficient of volume expansion.

As we know, The coefficient of volume expansion of the liquid

= change in volume/(original volume × temperature difference)

= (V₂ - V₁)/[V₁ × (T₂ - T₁)]

Change in volume = (V₂ - V₁)

Here, V₂ ( final volume) = 1.31 L

V₁  (initial volume)= 1.55 L

T₂ (final temperature) = 14.7 degrees

T₁ (initial temperature) = 96 degrees

The coefficient of volume expansion of the liquid

= (1.31 - 1.55) / [1.5 × (14.7- 96)]

= 1.97 × 10⁻³ /⁰C

Thus, the coefficient of volume expansion of the liquid = 1.97 × 10⁻³ /⁰C

To know more about coefficient of volume expansion refer to:

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8 0
1 year ago
A 0.40-kg particle moves under the influence of a single conservative force. At point A, where the particle has a speed of 10 m/
yan [13]

Answer:

The value of the potential energy of the particle at point B is 85 joules.

Explanation:

According to the Principle of Energy Conservation, the energy cannot be created nor destroyed, only transformed. The particle at point A has kinetic and potential energy and receives a work due to an external conservative force (Work-Energy Theorem), whose sum is equal to potential energy at point B. Mathematically speaking, the expression that describes the phenomenon is:

K_{A} + U_{A} + W_{A \rightarrow B} = U_{B}

Where:

K_{A} - Kinetic energy at point A, measured in joules.

U_{A} - Potential energy at point A, measured in joules.

W_{A \rightarrow B} - Work due to conservative force from A to B, measured in joules.

U_{B} - Potential energy at point B, measured in joules.

The initial kinetic energy of the particle is:

K_{A} = \frac{1}{2}\cdot m \cdot v^{2}

Where:

m - Mass, measured in kilograms.

v - Velocity, measured in meters per second.

If m = 0.4\,kg and v = 10\,\frac{m}{s}, then:

K_{A} = \frac{1}{2}\cdot (0.4\,kg)\cdot \left(10\,\frac{m}{s} \right)^{2}

K_{A} = 20\,J

Finally, the value of the potential energy at point B is:

U_{B} = 20\,J + 40\,J + 25\,J

U_{B} = 85\,J

The value of the potential energy of the particle at point B is 85 joules.

7 0
3 years ago
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