Gravitational acceleration (Ga) is inversely proportional to k / Distance^2
so Ga * Distance^2 = K
On the surface of Earth acceleration due to gravity is about 9.8m/s^2 with an average distance to the earths core of about 6371 km (Wolfram alpha).
So k = 9.8 * 6371^2
I'm presuming that your distance of 116 is km
As
Ga = k / distance^2
Ga = ((9.8 * 6371^2) / (6371 + 116)^2 ) = 397778481.8 / 42081169
= 9.45 m/s^2 to 2sf
Answer
-8.67× 10^6 N/C
Explanation:
The Electric Field is defined as force per unit charge.
E = Q/ 4π£r2
Qv= −6.5 μCm3
Qv = Q/ V= Q/ 4/3 πr3
Hence Q = 4/3 πr3 × Qv
Hence E = 4/3 πr3 × Qv / 4π£r2= Qvr/3£
−6.5 μ × 4/ 3×8.854 ×10^-12
-6.5 × 4 × 10^6/3 = -8.67× 10^6 N/C
Note: £ = 8.854×10^-12m/F
is the permittivity of free space
Qv is the charge per unit volume
V is volume and volume
Answer:
A
Explanation:
You are given Vi, Vf and t. The only thing left is a.
Answer:
Can you show the question it's not clear
When we hit the puck from tap the puck will move forward.
This is due to the impulse provided by us at the time of hit. Due to this impulse the puck will move forward and start moving in some direction.
As soon as puck move forward the force on it is zero as the weight of the puck is counterbalanced by the air stream force and there is no other force on it so puck will continue its motion till it will hit at some other point.
So here the motion of the puck will be uniform motion till it will collide with some other points.
So here the correct option will be given as
<em>moves with a constant speed until hitting the other end.</em>
