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3 years ago

What type of wave could measure 5 meters in length?

Physics

1 answer:

Tatiana [17]3 years ago

4 0

-- A sound wave at 68 Hz . . . like from the piano key 2 octaves below middle-C .

-- A radio wave at 60 MHz . . . the upper edge of the old analog TV channel-2 .

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Light traveling from water to a gemstone strikes the surface at an angle of 80.0º and has an angle of refraction of 15.2º . (a)

7nadin3 [17]

Answer:

The the speed of light in the gemstone is $v= 0.599*10^8 m/s$

The unreasonable thing about this is that the speed of ligth in the gemstone is too low

the speed is 19% of the speed of light which is very low

One main unreasonable or inconsistent factor is that the assumption that the differnce between the angle of incidence and angle of refraction is very large

Explanation:

From the question we are told that

The angle of incidence $i = 80^o$

The angle of refraction $r = 15.2^o$

From Snell's law we have ,

$n_1 sin \theta_1 = n_2 sin \theta_2$

Where $n_1$ is the refractive index of the first medium (water) with a constant value of $n_1 = 1..333$

$n_2$ is the refractive index of the second medium (gem stone)

$\theta_1$ is the angle between the beam and perpendicular surface of the first medium

$\theta_2$ is the angle between the beam an the perpendicular surface of the second medium

Making the $n_2$ the subject of the formula

$n_2 = n_1 \frac{sin \theta_1}{sin \theta_2}$

$= (1.333)(\frac{sin (80.0)}{sin 15.2} )$

$= 5.007$

Generally refractive index of a material is mathematically represented

$n = \frac{c}{v}$

Where c is the speed light

v is the speed of light observed in a medium

Making v the subject

$v = \frac{c}{n}$

substituting value for gem stone

$v = \frac{3.0*10^8}{5.007}$

$v= 0.599*10^8 m/s$

7 0

3 years ago

A machine produces a larger force than you exert to operate the machine. How does this input distance of the machine compare to

arlik [135]

Answer:

Because the output force is greater than the input force, the input distance must be greater than the output distance.

Explanation:

7 0

3 years ago

A 535 kg roller coaster car began at rest at the top of a 93.0 m hill. Now it is at the top of the first loop-de-loop.

iVinArrow [24]

Using g = 9.8 m/s2, the statement that best describes the roller coaster car when it is at the top of the loop-de-loop is that The car has both potential and kinetic energy, and it is moving at 24.6 m/s. The correct answer is <span>B) The car has both potential and kinetic energy, and it is moving at 24.6 m/s.</span>

4 0

3 years ago

Read 2 more answers

Pls help I will mark brainliest

earnstyle [38]

It will be unstable system because it will not be able to recover from the disturbance

7 0

3 years ago

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A 100 kg cart on a roller coaster has 1800J of kinetic energy. How fast is it going?<br> KE= 1/2mv2

34kurt

Answer: