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AlladinOne [14]
2 years ago
6

A remote control car with a mass of 2.45kg generates a thrust force of 31.8N. The car experiences a frictional force due to a co

efficient of friction of 0.24. Calculate: a) the friction, b) the net force, c) the acceleration of the car.
Physics
1 answer:
LenKa [72]2 years ago
8 0

Answer:

friction is the centripetal force for cars moving around a racetrack. 2. D. 3. D. 4. D. 5. Answers will vary. Sample Answer: The tether ball experiences ...

Explanation:

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If the frequency of a system undergoing simple harmonic motion doubles, by what factor does the maximum value of acceleration ch
faltersainse [42]

Answer:

the answers the correct one is a  4

Explanation:

The centripetal acceleration is by

           a = v² / R

angular and linear velocities are related

           v = w R

let's substitute

           a = w² R

for initial condition

           a₀ = w₀² R

suppose the initial angular velocity is wo, suppose the angular velocity doubles

           a = (2w₀)² R

           a = 4 (w₀² R)

           a = 4 a₀

when reviewing the answers the correct one is a

6 0
2 years ago
Two concentric current loops lie in the same plane. The smaller loop has a radius of 3.6 cm and a current of 12 A. The bigger lo
puteri [66]

Answer:

the radius of bigger loop = 6 cm

Explanation:

given,

two concentric current loops

smaller loop radius = 3.6 cm

]current in smaller loop = 12 A

current in the bigger loop = 20 A

magnetic field at the center of loop = 0

Radius of the bigger loop = ?

B_t = B_1 + B_2

0 = \dfrac{\mu_0I_1}{2R_1} +\dfrac{\mu_0I_2}{2R_2}

now, on solving

\dfrac{I_1}{R_1} = \dfrac{I_2}{R_2}

R_2 = I_2\dfrac{R_1}{I_1}

       = 20\times \dfrac{3.6}{12}

       = 6 cm

hence, the radius of bigger loop = 6 cm

7 0
3 years ago
A force of 5.25 newtons acts on an object of a mass 25.5 kilograms. How far is the object from the center of Earth? (The value o
nexus9112 [7]

Answer:

The force between two objects is calculated through the equation,

                       F = Gm₁m₂/d²

where m₁ and m₂ are the masses of the objects. In this case, an unknown mass and Earth. d is the distance between them and G is the universal gravitation constant.

In the second case, if the force is to become 2.5 times the original and all the variables are constant except d then,

                      2.5F = Gm₁m₂ / (D²)

                               D = 0.623d

Subsituting the known value of d,

                               D = 0.623(6.9 x 10^8) = 4.298 x 10^8 m

                         

5 0
1 year ago
An unknown element is found to have two naturally occurring isotopes, 200X and 210X with atomic masses of 200.028 and 210.039 re
Kruka [31]

Answer:

The average atomic mass of X is 206.0346

Explanation:

Atomic mass of 200X = 200.028

% abundance of 200X = 40% = 40/100 = 0.4

Atomic mass of 210X = 210.039

% abundance of 210X = 100% - 40% = 60% = 60/100 = 0.6

Average atomic mass of X = (0.4×200.028) + (0.6×210.039) = 80.0112 + 126.0234 = 206.0346

5 0
3 years ago
Can someone give me the units
Anettt [7]

Answer:

The unit for power is the Watt

8 0
3 years ago
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