Answer:
0.087 m
Explanation:
Length of the rod, L = 1.5 m
Let the mass of the rod is m and d is the distance between the pivot point and the centre of mass.
time period, T = 3 s
the formula for the time period of the pendulum is given by
.... (1)
where, I is the moment of inertia of the rod about the pivot point and g is the acceleration due to gravity.
Moment of inertia of the rod about the centre of mass, Ic = mL²/12
By using the parallel axis theorem, the moment of inertia of the rod about the pivot is
I = Ic + md²

Substituting the values in equation (1)


12d² -26.84 d + 2.25 = 0


d = 2.15 m , 0.087 m
d cannot be more than L/2, so the value of d is 0.087 m.
Thus, the distance between the pivot and the centre of mass of the rod is 0.087 m.
Answer:
B=0.2T
Explanation:
given required solution
l=4m B=? <em>F</em><em>=</em><em>BIL</em>
i=0.5A B=F/IL
F=0.4N B=0.4N/0.5A*4m
B=0.4/2=0.2T
The distance between object P1 and its image formed is determined as 36 m.
<h3>
Distance of the image</h3>
The distance of the image formed by object P1 is calculated as follows;
In a plane mirror; object distance = image distance
image distance of P1 = 18 m
distance between object and image = 18m + 18 m = 36 m
Thus, the distance between object P1 and its image formed is determined as 36 m.
Learn more about plane mirrors here: brainly.com/question/1126858
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Answer:

Explanation:
Hello,
In this case, since the acceleration in terms of position is defined as its second derivative:

The purpose here is derive x(t) twice as follows:

Thus, the acceleration turns out 4.8 meters per squared seconds.
Best regards.
I believe this question ask for the energy dissipated by
friction.
The overall energy equation for this is:
F = PE – KE
where F is friction loss, PE is potential energy = m g h,
KE is kinetic energy = 0.5 m v^2
<span>F = 66 kg * 9.8 m/s^2 * 170 m – 0.5 * 66 kg * (11 m/s)^2</span>
<span>F = 105,963 J ~ 106,000 J </span>