Question

Glacier National Park in Montana is approximately 4,100 ft above sea level with an atmospheric pressure of 681 torr. At what temperature does water (ΔHvap= 40.7 kJ/mol) boil at Glacier National Park?

Answer 1

Answer:

it is A

Explanation:

Answer 2

Answer : The temperature of liquid is, 369.9 K

Explanation :

The Clausius- Clapeyron equation is :

$\ln (\frac{P_2}{P_1})=\frac{\Delta H_{vap}}{R}\times (\frac{1}{T_1}-\frac{1}{T_2})$

where,

$P_1$ = vapor pressure of liquid at 373 K = 681 torr

$P_2$ = vapor pressure of liquid at normal boiling point = 760 torr

$T_1$ = temperature of liquid = ?

$T_2$ = normal boiling point of liquid = 373 K

$\Delta H_{vap}$ = heat of vaporization = 40.7 kJ/mole = 40700 J/mole

R = universal constant = 8.314 J/K.mole

Now put all the given values in the above formula, we get:

$\ln (\frac{760torr}{681torr})=\frac{40700J/mole}{8.314J/K.mole}\times (\frac{1}{T_1}-\frac{1}{373K})$

$T_1=369.907K\approx 369.9K$

Hence, the temperature of liquid is, 369.9 K