Systems can exist in three ways as open systems, closed systems, and isolated systems. The main difference between open and closed system is that in an open system, matter can be exchanged with the surrounding whereas, in a closed system, matter cannot be exchanged with the surrounding.
btw why not just look it up on google? btw btw brainliest plz
If we use mile or something else it will be hard to measure in sky .
Because the mile or meters too short for the space,
Galaxy and stars are too long far away from us if we use mile or meter,
It till be take like miliion year to measure.
In order to maintain neutrality, the negatively charged ions in the salt bridge will migrate into the anodic half-cell. A similar (but reversed) situation is found in the cathodic cell.
<h3>
What purpose does a salt bridge serve in an oxidation process?</h3>
Anions (negatively charged particles) are added to the solution of the oxidation half of the cell by the salt bridge, and cations (positively charged particles) are added to the solution of the reduction half of the reaction.
<h3>
What purpose does the salt bridge serve in a galvanic cell?</h3>
For instance, KCl, AgNO3, etc. In a galvanic cell, such as a voltaic cell or Daniel cell, salt bridges are typically used. A salt bridge's primary job is to assist in preserving the electrical neutrality of the internal circuit. Additionally, it aids in keeping the cell's response from reaching equilibrium.
Learn more about Salt bridge here:-
brainly.com/question/20345420
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Hey there!:
From the given data ;
Reaction volume = 1 mL , enzyme content = 10 ug ( 5 ug in 2 mg/mL )
Enzyme mol Wt = 45,000 , therefore [E]t is 10 ug/mL , this need to be express as "M" So:
[E]t in molar = g/L * mol/g
[E]t = 0.01 g/L * 1 / 45,000
[E]t = 2.22*10⁻⁷
Vmax = 0.758 umole/min/ per mL
= 758 mmole/L/min
=758000 mole/L/min => 758000 M
Therefore :
Kcat = Vmax/ [E]t
Kcat = 758000 / 2.2*10⁻⁷ M
Kcat = 3.41441 *10¹² / min
Kcat = 3.41441*10¹² / 60 per sec
Kcat = 5.7*10¹⁰ s⁻¹
Hence kcat of xyzase is 5.7*10¹⁰ s⁻¹
Hope that helps!
