Question

2. What pressure is required to compress 196.0 L of air at 1.00 atmosphere into a cylinder

Answer 1

Answer:

7.54 atm

Explanation:

The required pressure can be found by using the formula for Boyle's law which is

$P_2 = \frac{P_1V_1}{V_2}$

where

P1 is the initial pressure

P2 is the final pressure

V1 is the initial volume

V2 is the final volume

From the question we have

$P_2 = \frac{1 \times 196}{26} = \frac{196}{26} \\ = 7.538461...$

We have the final answer as

7.54 atm

Hope this helps you