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FromTheMoon [43]
2 years ago
7

2. What pressure is required to compress 196.0 L of air at 1.00 atmosphere into a cylinder

Chemistry
1 answer:
damaskus [11]2 years ago
3 0

Answer:

<h2>7.54 atm </h2>

Explanation:

The required pressure can be found by using the formula for Boyle's law which is

P_2 =  \frac{P_1V_1}{V_2}  \\

where

P1 is the initial pressure

P2 is the final pressure

V1 is the initial volume

V2 is the final volume

From the question we have

P_2 =  \frac{1 \times 196}{26}  =  \frac{196}{26}   \\ = 7.538461...

We have the final answer as

<h3>7.54 atm </h3>

Hope this helps you

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Exposing a 250 mL sample of water at 20.∘C to an atmosphere containing a gaseous solute at 27.59 kPa resulted in the dissolution
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Answer : The solubility of this gaseous solute will be, 5.18\times 10^{-5}g/mL

Explanation :

First we have to calculate the concentration of solute.

\text{Concentration of solute}=\frac{Mass}{Volume}=\frac{4.51\times 10^{-3}g}{250mL}=1.80\times 10^{-5}g/mL

Now we have to calculate the Henry's law constant.

Using Henry's law :

C=k_H\times p

where,

C = concentration of solute = 1.80\times 10^{-5}g/mL

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k_H = Henry's law constant = ?

Now put all the given values in the above formula, we get:

1.80\times 10^{-5}g/mL=k_H\times (27.59kPa)

K_H=6.52\times 10^{-7}g/mL.kPa

Now we have to calculate the solubility of this gaseous solute when its pressure is 79.39 kPa.

C_{(79.39kPa)}=k_H\times p

C_{(79.39kPa)}=(6.52\times 10^{-7}g/mL.kPa)\times (79.39kPa)

C_{(79.39kPa)}=5.18\times 10^{-5}g/mL

Therefore, the solubility of this gaseous solute will be, 5.18\times 10^{-5}g/mL

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What is one way to test whether an unknown solution is acidic or basic
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A solution's pH will be a number between 0 and 14. A solution with a pH of 7 is classified as neutral. If the pH is lower than 7, the solution is acidic. When pH is higher than 7, the solution is basic. These numbers describe the concentration of hydrogen ions in the solution and increase on a negative logarithmic scale. For example, If Solution A has a pH of 3 and Solution B has a pH of 1, then Solution B has 100 times as many hydrogen ions than A and is therefore 100 times more acidic.

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3 years ago
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