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3 years ago

Still need a good answer heterogeneous vs homogeneous, don't copy from web pls.

Chemistry

1 answer:

pantera1 [17]3 years ago

5 0

Answer:

homogenous is a uniform and consistent mixture ; heterogenous is a mixture that is non-uniform

Explanation:

usually if you can separate the mixture/particles it is heterogenous. For example, pizza is heterogenous because you can separate the dough from the tomato sauce from the cheese. vinegar is homogenous (cannot separate mixture)

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A chemist needs to create a series of standard Cu2+(aq)Cu2+(aq) solutions for an absorbance experiment. For the first standard,

lianna [129]

Answer:

The concentration of the Cu²⁺ solution in the 10,0 mL volumetric flask is 5,425×10⁻³ M Cu²⁺

Explanation:

The first dilution from a 2,17M Cu²⁺ solution gives:

2,17 M Cu²⁺ × $\frac{5,00 mL}{500,0 mL}$ = <em>0,0217 M Cu²⁺solution</em>

<em />

The second dilution gives as concentration:

0,0217 M Cu²⁺ × $\frac{25,00 mL}{100,0 mL}$ = 5,425×10⁻³ M Cu²⁺ solution

I hope it helps!

3 0

3 years ago

Read 2 more answers

What best explains the type of energy present in the wheels of a moving bus?

Nina [5.8K]

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4 years ago

A 52.0 g of Copper (specific heat=0.0923cal/gC) at 25.0C is warmed by the addition of 299 calories of energy. find the final tem

Leto [7]

Answer : The final temperature of the copper is, $87.29^oC$

Solution :

Formula used :

$Q=m\times c\times \Delta T=m\times c\times (T_{final}-T_{initial})$

where,

Q = heat gained = 299 cal

m = mass of copper = 52 g

c = specific heat of copper = $0.0923cal/g^oC$

$\Delta T=\text{Change in temperature}$

$T_{final}$ = final temperature = ?

$T_{initial}$ = initial temperature = $25^oC$

Now put all the given values in the above formula, we get the final temperature of copper.

$299cal=52g\times 0.0923cal/g^oC\times (T_{final}-25^oC)$

$T_{final}=87.29^oC$

Therefore, the final temperature of the copper is, $87.29^oC$

4 0

4 years ago

How many moles in 2.21 x10E24 atoms of aluminum

lisov135 [29]

<h3>Answer:</h3>

3.67 mol Al

<h3>General Formulas and Concepts:</h3>

<u>Pre-Algebra</u>

Order of Operations: BPEMDAS

Brackets
Parenthesis
Exponents
Multiplication
Division
Addition
Subtraction

Left to Right<u> </u>

<u>Chemistry</u>

<u>Atomic Structure</u>

Avogadro's Number - 6.022 × 10²³ atoms, molecules, formula units, etc.

<u>Stoichiometry</u>

Using Dimensional Analysis

<h3>Explanation:</h3>

<u>Step 1: Define</u>

2.21 × 10²⁴ atoms Al

<u>Step 2: Identify Conversions</u>

Avogadro's Number

<u>Step 3: Convert</u>

Set up: $\displaystyle 2.21 \cdot 10^{24} \ atoms \ Al(\frac{1 \ mol \ Al}{6.022 \cdot 10^{23} \ atoms \ Al})$
Divide: $\displaystyle 3.66988 \ mol \ Al$