Answer:
All of them apply according to the exam your are on because they all need concentration to work up the certain chemical
Explanation
The physical properties of a solution are not affected by the concentration of the components.
Boiling points and freezing points of solutions change as the concentration of the solute changes.
Moles of solute = (Liters of solution) x (Molarity of solution)
(Initial Concentration)(Initial Volume) = (Final Concentration) (Final Volume)
Concentration affects if an acid is weak or strong.
There
are a number of ways to express concentration of a solution. This would include the molarity. It is expressed as the number of moles of solute per volume of
the solution. <span>For example, we are given a solution of 2M NaOH
this describes a solution that has 2 moles of NaOH per 1 L volume of the
solution. We calculate as follows:
molarity = 5.67 g KCl ( 1 mol KCl / 74.55 g KCl ) / (100 mL solution) ( 1 L / 1000 mL ) = 0.76 mol KCl / L solution or 0.76 M
Therefore, the molarity of the given solution above would be 0.76 M.</span>
Answer:
Ksp = 3.24 x 10⁻⁴
Explanation:
The dissociation equilibrium for a generic salt AB is:
AB(s) ⇄ A⁺(aq) + B⁻(aq)
s s
For instance, the expression for the Ksp constant is:
Ksp = [A⁺] [B⁻] = s x s = s²
According to the problem, 0.0180 mol of the salt is soluble in 1.00 L os water. That means that the solubility of the salt (s) is equal to 0.0180 mol per liter.
s = moles of solute/L of solution = 0.0180 mol/L
Thus, we calculate Ksp from the s value as follows:
Ksp = s² = (0.0180)² = 3.24 x 10⁻⁴
Tin (iv), since the 4 tells us that the charge is 4 for tin.
Answer:
Exothermic reaction
Explanation:
An exothermic process releases heat, causing the temperature of the immediate surroundings to rise