A student compares the boiling point of substances having different intermolecular forces. <u>Boiling points of various substances</u> is the dependent variable that student most likely use.
<h3>Does the nature of intermolecular forces present in different substance affect their boiling points?</h3>
The boiling point of a substance is proportional to the strength of its intermolecular forces, the higher the boiling point, the stronger the intermolecular forces. We can compare the strengths of intermolecular forces by comparing the boiling points of different substances.
<h3>What properties are affected by intermolecular forces?</h3>
Intermolecular forces are measured by boiling points.
Intermolecular forces increase as bond polarization increases.
Ionic > hydrogen bonding > dipole dipole > dispersion is the order of the strength of intermolecular forces (and thus their impact on boiling points).
<h3>How can you determine strong and weak intermolecular forces?</h3>
Substances with strong intermolecular forces are very attracted to one another and are held together tightly. These substances require a great deal of energy to separate, whereas substances with weak intermolecular forces are held together very loosely and have weak interactions.
Learn more about intermolecular forces:
<u><em>brainly.com/question/13479228</em></u>
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33 - 15 = 18
This element is P-33
iE xplanation:am osrry nisot p ake inligsh
<span>oxidation, because oxygen is combining with the banana peel, and the peel is reacting with the air.</span>
Answer:
D. 0.75 grams
Explanation:
The data given on the iridium 182 are;
The half life of the iridium 182,
= 15 years
The mass of the sample of iridium, N₀ = 3 grams
The amount left, N(t) after two half lives is given as follows;
![N(t) = N_0 \left (\dfrac{1}{2} \right )^{\dfrac{t}{t_{1/2}} }](https://tex.z-dn.net/?f=N%28t%29%20%3D%20N_0%20%5Cleft%20%28%5Cdfrac%7B1%7D%7B2%7D%20%5Cright%20%29%5E%7B%5Cdfrac%7Bt%7D%7Bt_%7B1%2F2%7D%7D%20%7D)
For two half lives, t = 2 × ![t_{(1/2)}](https://tex.z-dn.net/?f=t_%7B%281%2F2%29%7D)
∴ t = 2 × 15 = 30
![\dfrac{t}{t_{(1/2)}} = \dfrac{30}{15} = 2](https://tex.z-dn.net/?f=%5Cdfrac%7Bt%7D%7Bt_%7B%281%2F2%29%7D%7D%20%3D%20%5Cdfrac%7B30%7D%7B15%7D%20%3D%202)
![\therefore N(t) = 3 \times\left (\dfrac{1}{2} \right )^2 = 0.75](https://tex.z-dn.net/?f=%5Ctherefore%20N%28t%29%20%3D%203%20%5Ctimes%5Cleft%20%28%5Cdfrac%7B1%7D%7B2%7D%20%5Cright%20%29%5E2%20%3D%200.75)
∴ The amount left, N(t) = 0.75 grams