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elena-s [515]
4 years ago
6

The management of a supermarket wants to adopt a new promotional policy of giving a free gift to every customer who spends more

than a certain amount per visit at this supermarket. The expectation of the management is that after this promotional policy is advertised, the expenditures for all customers at this supermarket will be normally distributed with a mean of
$
80
and a standard deviation of
$
12.12
. If the management decides to give free gifts to all those customers who spend more than
$
100
at this supermarket during a visit, what percentage of the customers are expected to get free gifts?
Mathematics
1 answer:
Vanyuwa [196]4 years ago
5 0
The described situation represents a normal distribution.
For a normally distributed distribution, P(X < x) = P(z < (x - mean) / standard deviation))
P(x > 100) = 1 - P(z =< 100) = 1 - P(z < (100 - 80) / 12.12) = 1 - P(z < 1.6502) = 1 - 0.95055 = 0.04945 = 4.9%

Therefore, the required percentage of the customers expected to get free gifts is 4.9%.
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Answer:

rate of the plane in still air is 33 miles per hour and the rate of the wind is 11 miles per hour

Step-by-step explanation:

We will make a table of the trip there and back using the formula distance = rate x time

                 d              =            r       x       t

there

back

The distance there and back is 264 miles, so we can split that in half and put each half under d:

               d            =         r        x        t

there    132

back     132

It tells us that the trip there is with the wind and the trip back is against the wind:

           

              d           =        r         x        t

there     132        =    (r + w)

back      132       =     (r - w)

Finally, the trip there took 3 hours and the trip back took 6:

           

             d         =        r        *        t

there    132     =    (r + w)     *       3

back     132     =    (r - w)      *       6

There's the table.  Using the distance formula we have 2 equations that result from that info:

132 = 3(r + w)        and        132 = 6(r - w)

We are looking to solve for both r and w.  We have 2 equations with 2 unknowns, so we will solve the first equation for r, sub that value for r into the second equation to solve for w:

132 = 3r + 3w and

132 - 3w = 3r so

44 - w = r.  Subbing that into the second equation:

132 = 6(44 - w) - 6w and

132 = 264 - 6w - 6w and

-132 = -12w so

w = 11

Subbing w in to solve for r:

132 = 3r + 3(11) and

132 = 3r + 33 so

99 = 3r and

r = 33

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