Answer : The correct option is, (A) silver ion gains electrons more easily and is a stronger oxidizing agent than a chromium(III) ion.
Explanation :
The given half reaction are :
1st half reaction :
The reduction potential of this reaction = +0.80 V
2nd half reaction :
The reduction potential of this reaction = -0.74 V
From the reduction potentials, we conclude that the reaction which have positive reduction potential, they will gain electrons more easily and reduced itself and act as a stronger oxidizing agent.
Or we can say that the reaction which have negative reduction potential, they will lose electrons more easily and oxidized itself and act as a stronger reducing agent.
The reduction potential of 1st half reaction is positive and 2nd half reaction is negative.
Therefore, the silver ion gains electrons more easily and is a stronger oxidizing agent than a chromium(III) ion.
I do believe the answer is cell
Answer:
The location of the electrons in the Thomson's plum pudding model of the atom are contained in orbitals. These orbitals are what make the element stable or unstable
Answer:
This metal could be lead
Specific heat = 0.0308 cal/g°C
Explanation:
Step 1: Data given
The metal was heated to 115.0°C
in a calorimeter where it cooled to 32.6°C.
Mass of the metal = 25.0 grams
Heat released = 63.5 cal
Step 2: Calculate the specific heat of the metal
Q = m*c*ΔT
⇒with Q = the heat released = 63.5 cal
⇒with m = the mass of the metal = 25.0 grams
⇒with ΔT = the change of temperature = T2 - T1 = 32.6 °C - 115.0°C = -82.4 °C
⇒ c = the specific heat = TO BE DETERMINED
63.5 = 25.0 * c * 82.4
C = 0.0308 cal/g°C
This metal could be lead