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3 years ago

Can someone label these?

Chemistry

1 answer:

STatiana [176]3 years ago

8 0

1. Igneous roc
2. Weathering & erosion
3. Sediments
4. Sedimentary rock
5. Melting
6. Heat & pressure

Hope this is helpful

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Which of the following correctly matches the component a respiration with its job description

sp2606 [1]

hi there! i would love to help you but there are no choices or a photo attached!

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3 years ago

How much heat, in calories, is given off when 1.25 grams of silver is cooled from 100.0°C to 80.0°C? (The specific heat of silve

White raven [17]

1.43cal is the answer

4 0

4 years ago

Read 2 more answers

a photon has an energy of 1.10 x 10_-13 J. What is the photon's wavelenght? What type of electromagnetic radiation is it?

Luden [163]

Answer:

λ = 0.002 nm

The given photon is either x-ray or gamma ray because the range of x-ray and gamma ray is 1 nm-0.1 pm.

Explanation:

Given data:

Energy of photon = 1.10 × 10⁻¹³ J.

Wavelength of photon = ?

Solution:

Formula:

E = h.c / λ

λ = h. c / E

λ = 6.626 × 10⁻³⁴ j. s × 3×10⁸ m/s / 1.10 × 10⁻¹³ J.

λ = 19.878 × 10⁻²⁶m / 1.10 × 10⁻¹³ J

λ = 18.071 × 10⁻¹³ m

λ = 18.071 × 10⁻¹³ × 10⁹

λ = 18.071 × 10⁻⁴ nm

λ = 0.002 nm

The given photon is either x-ray or gamma ray because the range of x-ray and gamma ray is 1 nm-0.1 pm.

8 0

4 years ago

Small quantities of oxygen can be prepared in the laboratory by heating potassium chlorate, KClO 3 ( s ) . The equation for the

Pavlova-9 [17]

Answer:

Mass of $O_2$ produced = 32 g

Explanation:

Calculation of the moles of $KClO_3$ as:-

Mass = 82.4 g

Molar mass of $KClO_3$ = 122.55 g/mol

The formula for the calculation of moles is shown below:

$moles = \frac{Mass\ taken}{Molar\ mass}$

Thus,

$Moles= \frac{82.4\ g}{122.55\ g/mol}$

$Moles= 0.67237\ mol$

From the reaction shown below:-

$2KClO_3\rightarrow 2KCl+3O_2$

2 moles of potassium chlorate on reaction forms 3 moles of oxygen gas

So,

0.67237 moles of potassium chlorate on reaction forms $\frac{3}{2}\times 0.67237$ moles of oxygen gas

Moles of oxygen gas = 1 mole

Molar mass of oxygen gas = 32 g/mol

<u>Mass of $O_2$ produced = 32 g</u>

6 0

4 years ago

Calculate the pH of a 0.10 M solution of acidic acid HC2H3O2(aq) at 25 °C. Ka for HC2H3O2 = 1.8×10−5 at 25 °C g

TiliK225 [7]

Answer:

The answer is "3".

Explanation:

acetic acid Dissociation:

$CH_3COOH \ < - - - - - - - - - - - - - \ > CH_3COO^{-}+H^{+}\\\\$

Dissociation constant of the Ka:

$Ka = \frac{[CH3COO^{-}] [H^{+}]}{[CH_3COOH]}\\\\$

using the ICE table:

$CH_3COOH \ < - - - - - - - - - - - - - \ > CH_3COO^{-}+H^{+}\\\\$ $\to 1.8 \times 10^{-5} =\frac{( x \times x) }{0.1-x} -------(2)$

x is negligible compared to Ka.

$1.8\times 10^{-5} = \frac{x^2}{0.10}\\\\x^2 = 1.8 \times 10^{-6}\\\\x = 1.34 \times 10^{-3}\\\\pH = -\log [H^{+}]$

From the ICE table, $[H^{+}] = x = 1.34 \times 10^{-3}$

$\to pH = -\log(1.34 \times 10^{-3}) = 3$

5 0

3 years ago