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lisov135 [29]
3 years ago
14

There are naturally occuring elements.

Chemistry
2 answers:
Salsk061 [2.6K]3 years ago
8 0

THERE ARE 92 NATURALLY OCCURING ELEMENTS :D

mr_godi [17]3 years ago
6 0
There are 94 naturally occurring elements
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How many sodium ions are in 4543.3 g of NaCl?
Stella [2.4K]

Answer:

4.68x10²⁵ ions of Na⁺

Explanation:

First of all, we dissociate the salt:

NaCl(aq) → Na⁺(aq) + Cl⁻(aq)

An aqueous solution of NaCl dissociates in chlorides anions and sodium cations. Ratio is 1:1, per 1 mol of NaCl, we have 1 mol of Na⁺

We determine the moles of salt: 4543.3 g . 1mol / 58.45 g = 77.7 moles

77.7 moles are the amount of NaCl, therefore we have 77.7 moles of Na⁺.

We count the ions:

1 mol fo Na⁺ has 6.02x10²³ ions

77.7 moles of Na⁺ must have (77.7 . 6.02x10²³) / 1 = 4.68x10²⁵ ions of Na⁺

3 0
3 years ago
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Equation 3x-5=-2x+ 10?<br> O<br> 0<br> x= 5<br> -5 = x<br> -15 = -5x<br> -5x = 15
Harman [31]

Answer:

are those the answer choice

7 0
3 years ago
List some Industrial plants and indicate the gaseous pollutants they emit​
mixas84 [53]

Answer:

Sources of air pollutants from the industry include: power generation plant, boilers, bleaching plants and caustic soda/chlorine plant. Pollutants include particulate matter, chlorine, sulfur dioxides, hydrogen sulfides, carbon dioxide, carbon monoxides and nitrous oxides.

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3 years ago
What is the name of the ionic compound AlBr3?
Aleksandr [31]

Answer: Correct name will be is aluminum bromide

Explanation:

In a molecular formula ,AlBr_3

Aluminium atoms present = 1  

Bromine atoms present = 3

Charge on aluminium is +3 and charge on bromine is -1.

While naming:

  • Name of the cation is written first. Simple name of the element is written
  • After name of cation name of an anions written with suffix 'ide' in the end.

So, the name of AlBr_3 will be aluminium bromide.

7 0
3 years ago
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Explain in words or using your diagrams how beryllium atoms would react with fluorine atoms.
Marysya12 [62]

Explanation:

To delineate the the nature of the bonds that would be formed between the two elements, let us first write the electronic configuration of the two species;

  Be  = 2, 2

  F  = 2, 7

 Beryllium is a metal with two valence electrons whereas fluorine is a halogen with seven valence electrons.

When Be loses two electrons it becomes isoelectronic with He;

                 Be →  Be²⁺ + 2e⁻  

Also, when fluorine gains  an electron, it becomes isoelectronic with Ne;

               F  + e⁻ →  F⁻

This loss and gain of electrons between the two elements creates an electrostatic attraction them and they enter into an electrovalent bond.

      Hence;

           Be²⁺  + 2F⁻ → BeF₂

8 0
3 years ago
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