What is the percent composition by mass of nitrogen in NH4OH?
1 answer:
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0.309g
Explanation:
Mass of evaporating dish = 6.251g
Mass of evaporating dish and sample of hydrate = 16.864g
solving for mass of hydrate before heating;
Mass of hydrate =
mass of evaporating dish and sample of hydrate - mass of evaporating dish;
Mass of hydrate before heating = 16.864g - 6.251g = 10.613g
Upon heating ;
Mass of hydrate plus dish = 11.3g
Unknown:
number of moles of water removed from the hydrate = ?
We need to find the mass of water removed from the hydrate;
Mass of hydrate after heating =mass of hydrate plus dish after heating - mass of evaporating dish
mass of hydrate after heating = 11.3g - 6.251g = 5.049g
Mass of water lost = Mass of hydrate before heating - mass of hydrate after heating
= 10.613g - 5.049g
= 5.564g
Number of moles of water =
number of moles of water = 0.309moles
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