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Lena [83]
3 years ago
9

A certain first-order reaction 45% complete in 65seconds, determine the rate constant and the half life for the process ​

Chemistry
1 answer:
masha68 [24]3 years ago
3 0

The rate constant : k = 9.2 x 10⁻³ s⁻¹

The half life : t1/2 = 75.3 s

<h3>Further explanation</h3>

Given

Reaction 45% complete in 65 s

Required

The rate constant and the half life

Solution

For first order ln[A]=−kt+ln[A]o

45% complete, 55% remains

A = 0.55

Ao = 1

Input the value :

ln A = -kt + ln Ao

ln 0.55 = -k.65 + ln 1

-0.598=-k.65

k = 9.2 x 10⁻³ s⁻¹

The half life :

t1/2 = (ln 2) / k

t1/2 = 0.693 : 9.2 x 10⁻³

t1/2 = 75.3 s

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Argon (Ar) and helium (He) are initially in separate compartments of a container at 25°C. The
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Answer:

(a) V_B=11.68L

(b) x_{He}=0.533

Explanation:

Hello,

In this case, since the both gases behave ideally, with the given information we can compute the moles of He in A:

n_A=\frac{0.082\frac{atm*L}{mol*K}*298K}{1.974 atm*6.00L}=2.063mol

Thus, since the final pressure is 3.60 bar, we can write:

P=x_{Ar}P_A+x_{He}P_B\\\\P=\frac{n_{Ar}}{n_{Ar}+n_{He}} P_A+\frac{n_{He}}{n_{Ar}+n_{He}} P_B\\\\3.60bar=\frac{2.063mol}{2.063mol+n_{He}} *2.00bar+\frac{n_{He}}{2.063mol+n_{He}} *5.00bar

The moles of helium could be computed via solver as:

n_{He}=2.358mol

Or algebraically:

3.60bar=\frac{1}{2.063mol+n_{He}} *(4.0126+5.00*n_{He})\\\\7.314+3.60n_{He}=4.013+5.00*n_{He}\\\\7.314-4.013=5.00*n_{He}-3.60n_{He}\\\\n_{He}=\frac{3.3}{1.4}=2.358mol

In such a way, the volume of the compartment B is:

V_B=\frac{n_{He}RT}{P_B}=\frac{2.358mol*0.082\frac{atm*L}{mol*K}*298.15K}{4.935atm}\\  \\V_B=11.68L

Finally, he mole fraction of He is:

x_{He}=\frac{2.358}{2.358+2.063}\\ \\x_{He}=0.533

Regards.

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3 years ago
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Answer:

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Explanation:

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Explanation:

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How many ants would 6 giant anteaters need to eat in one year to get the matter and energy they need? Write a simple formula to
prohojiy [21]

Answer:

180,000 ants

Explanation:

For this problem we can create the following simple formula to solve this problem...

f(x) = 6x

where the variable x represents the number of ants that a single Anteater needs to eat per day. After a quick online search we can see that a single Anteater eats roughly 30,000 ants per day. If we use this value and plug it into the simple formula we can get the total number of ants 6 anteaters need to eat to survive.

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For the reaction, identify the Lewis acid and the Lewis base.<br> AlF3 + CH3F → CH3+ + [AlF4]-
Ivanshal [37]
Answer:
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Explanation:
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In Given Reaction,
<span>                               AlF</span>₃<span> + CH</span>₃<span>F → CH</span>₃⁺<span> + [AlF</span>₄<span>]</span>⁻

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CH₃F is acting as a base because the F atom containing three lone pair of electrons can donate it to Al metal resulting in the formation of electrophile i.e. CH₃⁺.
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