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Zigmanuir [339]
3 years ago
15

Which contains mostly hydrocarbons? A. proteins B.salt C.gasoline

Chemistry
2 answers:
mixer [17]3 years ago
5 0

it should be Carbohydrates.

Ksju [112]3 years ago
5 0
Gasoline of course %oydkydykdlydhkdhldkhzlzh
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As methane burns, it reacts with oxygen and forms carbon dioxide and water. The balanced chemical equation below models this che
Elan Coil [88]

Explanation:

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3 0
2 years ago
Which of the following has the shortest bond lenght Options A). H2 B).N2 C).O2 D).F2
hammer [34]

Answer:

B. N2

Explanation:

The triple bonds pull the atoms closer together, and since N2 is the only molecule with the triple bond, it is the shortest bond length.

6 0
3 years ago
What best describes a solution ?
topjm [15]
A solution is the answer to a problem
8 0
3 years ago
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Using the standard enthalpies of formation found in the textbook, determine the enthalpy change for the combustion of ethanol c2
ArbitrLikvidat [17]
Enthalpy of formation is calculated by subtracting the total enthalpy of formation of the reactants from those of the products. This is called the HESS' LAW.
ΔHrxn = ΔH(products) - ΔH(reactants)

Since the enthalpies are not listed in this item, from reliable sources, the obtained enthalpies of formation are written below.
ΔH(C2H5OH) = -276 kJ/mol
ΔH(O2) = 0 (because O2 is a pure substance)
ΔH(CO2) = -393.5 kJ/mol
ΔH(H2O) = -285.5 kJ/mol

Using the equation above,
ΔHrxn = (2)(-393.5 kJ/mol) + (3)(-285.5 kJ/mol) - (-276 kJ/mol)
ΔHrxn = -1367.5 kJ/mol

<em>Answer: -1367.5 kJ/mol</em>
6 0
3 years ago
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How many atoms are found in 3.45g of CO2?
USPshnik [31]

<u>Answer:</u> The number of carbon and oxygen atoms in the given amount of carbon dioxide is 4.72\times 10^{22} and 9.44\times 10^{22} respectively

<u>Explanation:</u>

To calculate the number of moles, we use the equation:

\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}

Given mass of carbon dioxide gas = 3.45 g

Molar mass of carbon dioxide gas = 44 g/mol

Putting values in above equation, we get:

\text{Moles of carbon dioxide gas}=\frac{3.45g}{44g/mol}=0.0784mol

1 mole of carbon dioxide gas contains 1 mole of carbon and 2 moles of oxygen atoms.

According to mole concept:

1 mole of a compound contains 6.022\time 10^{23} number of molecules

So, 0.0784 moles of carbon dioxide gas will contain 1\times 0.0784\times 6.022\times 10^{23}=4.72\times 10^{22} number of carbon atoms and 2\times 0.0784\times 6.022\times 10^{23}=9.44\times 10^{22} number of oxygen atoms

Hence, the number of carbon and oxygen atoms in the given amount of carbon dioxide is 4.72\times 10^{22} and 9.44\times 10^{22} respectively

3 0
3 years ago
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