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dem82 [27]
3 years ago
9

Which type of molecule is shown below?

Chemistry
2 answers:
zubka84 [21]3 years ago
8 0

Answer:

\boxed{\mathrm{Alkene}}

Explanation:

The hydrocarbon shown has a double bond. Hydrocarbons with double bonds are known as alkenes.

Cyclic alkanes have cyclic structure.

Alkanes only have single bonds.

Alkynes have triple bonds.

GenaCL600 [577]3 years ago
7 0

Answer:

Alkene

Explanation:

A molecule having a double bond between its atoms is called an alkene.

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Primary alkyl halides tend to undergo the SN2 reaction mechanism in nucleophilic substitution since there is less steric hindrance for nucleophilic attack and the carbocations that they form are not as stable as those formed from tertiary alkyl halides. 


1-bromopentane > 1-bromo 2-methylbutane > <span>1-bromo-3-methylbutane</span>> 2-bromo 2-methylbutane
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Mass box A = 10 grams; Mass box B = 5 grams; Mass box C—made of one A and one B Mass ratio A/B =
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Answer:

mass ratio of A/B is 2:1

Explanation:

Since the mass of box A = 10g

                mass of box B = 5g

   Mass of box C = mass of box A + mass of box

A ratio compares two quantities. To find the ratio of the two boxes:

  Ratio of A to B = \frac{mass of A}{mass of B}

  Ratio of A to B = \frac{10grams}{5grams} = 2

The mass ratio is 2:1 i.e box A has twice the mass of B

8 0
3 years ago
Calculate the temperature change that occurs when 254 cal of heat are added to 24 g of water
Tomtit [17]
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Calculate the temperature change that occurs when 254 cal of heat are added to 24 g of water
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3 years ago
An ideal gas (C}R), flowing at 4 kmol/h, expands isothermally at 475 Kfrom 100 to 50 kPa through a rigid device. If the power pr
Zina [86]

<u>Answer:</u> The rate of heat flow is 3.038 kW and the rate of lost work is 1.038 kW.

<u>Explanation:</u>

We are given:

C_p=\frac{7}{2}R\\\\T=475K\\P_1=100kPa\\P_2=50kPa

Rate of flow of ideal gas , n = 4 kmol/hr = \frac{4\times 1000mol}{3600s}=1.11mol/s    (Conversion factors used:  1 kmol = 1000 mol; 1 hr = 3600 s)

Power produced = 2000 W = 2 kW     (Conversion factor:  1 kW = 1000 W)

We know that:

\Delta U=0   (For isothermal process)

So, by applying first law of thermodynamics:

\Delta U=\Delta q-\Delta W

\Delta q=\Delta W      .......(1)

Now, calculating the work done for isothermal process, we use the equation:

\Delta W=nRT\ln (\frac{P_1}{P_2})

where,

\Delta W = change in work done

n = number of moles = 1.11 mol/s

R = Gas constant = 8.314 J/mol.K

T = temperature = 475 K

P_1 = initial pressure = 100 kPa

P_2 = final pressure = 50 kPa

Putting values in above equation, we get:

\Delta W=1.11mol/s\times 8.314J\times 475K\times \ln (\frac{100}{50})\\\\\Delta W=3038.45J/s=3.038kJ/s=3.038kW

Calculating the heat flow, we use equation 1, we get:

[ex]\Delta q=3.038kW[/tex]

Now, calculating the rate of lost work, we use the equation:

\text{Rate of lost work}=\Delta W-\text{Power produced}\\\\\text{Rate of lost work}=(3.038-2)kW\\\text{Rate of lost work}=1.038kW

Hence, the rate of heat flow is 3.038 kW and the rate of lost work is 1.038 kW.

4 0
2 years ago
Estradiol is a female sexual hormone that causes maturation and maintenance of the female reproductive system. Elemental analysi
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Answer:

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Percentage of an element in a compound:

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