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3 years ago

Which characteristic do all organisms as share

1 answer:

Natasha2012 [34]3 years ago

4 0

Answer: All living organisms share several key characteristics: sensitivity or response to the environment, reproduction, growth and development, regulation, homeostasis, and energy processing.

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Nitrogen ion (Nitride) is ... Cation/Anion/Neither? # of protons? # of electrons? Charge (1-, 2-, 3-, 1+, 2+, 3+, or 0) Number o

OLga [1]

Answer:

3- is the charge and 8 dots on its Lewis dot structure.

Explanation:

Hello there!

In this case, since nitrogen is an element with five valence electrons (electrons on its outer shell), we infer that it needs three bonds to complete the octet, for which its charge, when forming nitride ions is 3-, which means it has received three electrons. Thus, when drawing the Lewis dot structure, it is evident that is will have 5+3 = 8 dots due to the electron reception.

Regards!

8 0

2 years ago

HELP!!!! The freezing of methane is an exothermic change. What best describes the temperature conditions that are likely to make

vazorg [7]

<u>Answer:</u> The correct statement is low temperature only, because entropy decreases during freezing.

<u>Explanation:</u>

The relationship between Gibb's free energy, enthalpy, entropy and temperature is given by the equation:

$\Delta G=\Delta H-T\Delta S$

Where,

$\Delta G$ = change in Gibb's free energy

$\Delta H$ = change in enthalpy

T = temperature

$\Delta S$ = change in entropy

It is given that freezing of methane is taking place, which means that entropy is decreasing and $Delta S$ is becoming negative. It is also given that the reaction is an exothermic reaction, this means that the $\Delta H$ is also negative.

For a reaction to be spontaneous, $\Delta G$ must be negative.

$-ve=-ve-[T(-ve)]\\\\-ve=-ve+T$

From above equations, it is visible that $\Delta G$ will be negative only when the temperature will be low.

Hence, the correct statement is low temperature only, because entropy decreases during freezing.

8 0

3 years ago

How many grams of Na2So4 would be formed if 0.75 moles of NaOH reacted?

Nata [24]

Answer:

$\boxed{\text{53 g }}$

Explanation:

You don't give the reaction, but we can get by just by balancing atoms of Na.

We know we will need the partially balanced equation with masses, moles, and molar masses, so let’s gather all the information in one place.

M_r: 142.04

2NaOH + … ⟶ Na₂SO₄ + …

n/mol: 0.75

1. Use the molar ratio of Na₂SO₄ to NaOH to calculate the moles of NaF.

Moles of Na₂SO₄ = 0.75 mol NaOH × (1 mol Na₂SO₄/2 mol NaOH

= 0.375 mol Na₂SO₄

2. Use the molar mass of Na₂SO₄ to calculate the mass of Na₂SO₄.

Mass of Na₂SO₄ = 0.375 mol Na₂SO₄ × (142.04 g Na₂SO₄/1 mol Na₂SO₄) = 53 g Na₂SO₄

The reaction produces $\boxed{\text{53 g }}$ of Na₂SO₄.

4 0

3 years ago

As water starts to freeze, the molecules of water

amid [387]

Move more freely :) hope this helps!

8 0

2 years ago

350.0-mL of 0.50 M hydrogen sulfate solution is reacted with 15.0 grams of sodium hydroxide. What volume of water will be produc

Evgesh-ka [11]

The volume of water that will be produced from the reaction will be 6.3 mL

<h3>Stoichiometric calculation</h3>

From the equation of the reaction:

$H_2SO_4 + 2NaOH --- > Na_2SO_4 + 2H_2O$

The mole ratio of hydrogen sulfate to sodium hydroxide is 1:2.

Mole of hydrogen sulfate = 0.50 x 350/1000 = 0.175 moles

Mole of 15 grams sodium hydroxide = 15/40 = 0.375 moles

Thus, hydrogen sulfide is the limiting reagent.

Mole ratio of hydrogen sulfide to water = 1:2.

Equivalent mole of water = 0.175 x 2 = 0.35 moles

Mass of 0.35 moles of water = 0.35 x 18 = 6.3 grams.

1 gram of water = 1 ml.

Thus, 6.3 grams of water will be equivalent to 6.3 mL

More on stoichiometric calculation can be found here: brainly.com/question/27287858

#SPJ1

6 0

2 years ago