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mojhsa [17]
3 years ago
15

Objects that can bew seen only under magnification

Chemistry
1 answer:
timofeeve [1]3 years ago
4 0
The answer is (D) microscopic. You can remember this, because the name is very close to "microscope," an instrument used to greatly magnify and observe tiny organisms and objects.
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If a sample of N2 gas has an initial pressure of 500 Torr and volume of 0.5 L, what will the final volume be if the pressure is
kherson [118]

Answer:

V₂ = 0.4 L

Explanation:

<u>Data:</u>

  • P₁ (initial pressure) = 500 torr
  • V₁ (initial volume) = 0.5 L
  • P₂ (final pressure) = 700 torr

<u>Wanted:</u>

  • V₂ (final volume)

<u>Equation:</u>

  • P₁V₁ = P₂V₂  →  V₂ = P₁V₁ / P₂

<u>Solution:</u>

  • V₂ = \frac{(500 torr)(0.5 L)}{700 torr} = 0.3571 L or 0.4 L
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2 years ago
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I think it is C or F
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3 years ago
Determine the mass of a ball with a wavelength of 3.45 × 10-34 m and a velocity of 6.55 m/s
Yuki888 [10]
<span>293 grams The formula for the wavelength of a massive particle is λ = h/p where λ = wavelength h = Plank constant (6.626070040Ă—10^â’34 J*s) p = momentum (mass times velocity) So let's solve for momentum and from there get the mass λ = h/p λp = h p = h/λ Substitute known values and solve p = 6.626070040Ă—10^â’34 J*s/3.45Ă—10^-34 m p = 1.92 J*s/m Since momentum is the product of mass and velocity, we have p = M * V p/V = M So substitute again, and solve. p/V = M 1.92 J*s/m / 6.55 m/s = M 1.92 kg*m/s / 6.55 m/s = M 1.92 kg*m/s / 6.55 m/s = M 0.293 kg = M So the mass is 293 grams</span>
6 0
4 years ago
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Are these correct? Thank you!! If they are not, which do I fix?
Gennadij [26K]
This looks correct to me! <3 have a good day
3 0
3 years ago
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Which of the following choices is NOT a characteristic of unicellular:
marysya [2.9K]

Answer:

B. Consists of many cells

Explanation:

Unicellular organisms consist of one singular cell. While multicellular organisms consist of many cells

4 0
2 years ago
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