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KonstantinChe [14]
3 years ago
13

For the function f(x) = -3x, find the difference quotient f(a+h)-f(a) / h

Mathematics
1 answer:
likoan [24]3 years ago
7 0

Step-by-step explanation:

f(a+h) – f(a)/h = –3

so the answer is –3

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PLEASE HELP I NEED HELP !!!!!!!! The graph of a line passes through the two points (-2, 1) and (2, 1). What is the equation of t
MrRissso [65]

Answer:

y - 1 = 0

Step-by-step explanation:

We know that Equation of a line is given by,

y - y₁ / x - x₁ = y₂ - y₁ / x₂ - x₁

Let A(-2,1) and B(2,1)

x₁ = -2 ; x₂ = 2 ; y₁ = 1 ; y₂ = 1

Substituting the values,

y - 1 / x - (-2) = 1 - 1 / 2 - (-2)

y - 1 / x + 2 = 0

y - 1 = 0

7 0
3 years ago
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What is the value of x and the length of the segment?
mylen [45]

Answer:

5x - 13 = x+19

5x-x=19+13

4x=32

x=32/4

x=8

Cb=5x-13

=5×8-3

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AB=X+19

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3 years ago
47/7 as a mixed number in siplest form
puteri [66]
For this fraction, you would have to see how many times 7 goes into 47. So, 6 times as 7 times 6 is 42. Subtract 42 from 47, and this would be your remainder:

6\frac{5}{7} 
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3 years ago
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Help please and thanks! I always give brainliest!
Tju [1.3M]

Answer:

x=18, y=9

Step-by-step explanation:

The lines of y+3 and 12 look equal to each other. So do x-3 and 15. Because of this, we set each equal to each other and solve.

solving for x:

x-3 = 15

+ 3     +3

x=18

solving for y:

y+3=12

- 3    -3

y=9

hope this helps!!!

6 0
2 years ago
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The volume of water in a tank is modeled by the function y = 1.15x3 – 0.1x2 + 2 where x is the number of minutes after the fauce
Thepotemich [5.8K]

Given:

The volume of water in a tank is modeled by the function

y=1.15x^3-0.1x^2+2

where, x is the number of minutes after the faucet filling the tank is turned on.

To find:

The y-intercept and what does it represent in this context?

Solution:

We have,

y=1.15x^3-0.1x^2+2

Substituting x=0, we get

y=1.15(0)^3-0.1(0)^2+2

y=0-0+2

y=2

Therefore, the y-intercept is 2 and it represents the volume of water in a tank before the faucet filling the tank is turned on.

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