What is the correct answer?

Assuming that 1.0g of aspirin dissolves in 450 mL of water at 10o C, how much aspirin would be lost in the 1.4 mL of water added

ipn [44]

Answer:

amount of aspirin dissolved = 0.0031 g

so we can say that this is not affect % yield as amount of aspirin lost is very less

Explanation:

given data

mass of aspirin = 1 g

volume of water = 450 mL

solubility of aspirin temperature = 10° C

volume of water added = 1.4 mL

to find out

how much amount aspirin would be lost

solution

we know the solubility of aspirin is

solubility of aspirin = $\frac{mass\ of\ aspirin}{volume\ of\ water}$

solubility of aspirin = $\frac{1\ g}{450\ mL}$

solubility of aspirin = 2.2 × $10^{-3}$ g/mL

so

we can say

amount of aspirin dissolved = solubility of aspirin × volume of water added

put here value

amount of aspirin dissolved = 2.2 × $10^{-3}$ × 1.4

amount of aspirin dissolved = 3.1 × $10^{-3}$ g

amount of aspirin dissolved = 0.0031 g

so we can say that this is not affect % yield as amount of aspirin lost is very less

7 0

3 years ago

Given the thermochemical equations X2+3Y2⟶2XY3ΔH1=−370 kJ X2+2Z2⟶2XZ2ΔH2=−120 kJ 2Y2+Z2⟶2Y2ZΔH3=−270 kJ Calculate the change in

Alchen [17]

Answer : The change in enthalpy of the reaction is, -310 kJ

According to Hess’s law of constant heat summation, the heat absorbed or evolved in a given chemical equation is the same whether the process occurs in one step or several steps.

According to this law, the chemical equation can be treated as ordinary algebraic expression and can be added or subtracted to yield the required equation. That means the enthalpy change of the overall reaction is the sum of the enthalpy changes of the intermediate reactions.

The given main reaction is,

$4XY_3+7Z_2\rightarrow 6Y_2Z+4XZ_2$ $\Delta H=?$

The intermediate balanced chemical reaction will be,

(1) $X_2+3Y_2\rightarrow 2XY_3$ $\Delta H_1=-370kJ$

(2) $X_2+2Z_2\rightarrow 2XZ_2$ $\Delta H_2=-120kJ$

(3) $2Y_2+Z_2\rightarrow 2Y_2Z$ $\Delta H_3=-270kJ$

Now we will reverse the reaction 1 and multiply reaction 1 by 2, reaction 2 by 2 and reaction 3 by 3 then adding all the equations, we get :

(1) $4XY_3\rightarrow 2X_2+6Y_2$ $\Delta H_1=2\times (+370kJ)=740kJ$

(2) $2X_2+4Z_2\rightarrow 4XZ_2$ $\Delta H_2=2\times (-120kJ)=-240kJ$

(3) $6Y_2+3Z_2\rightarrow 6Y_2Z$ $\Delta H_3=3\times (-270kJ)=-810kJ$

The expression for enthalpy of formation of $CH_4$ will be,

$\Delta H=\Delta H_1+\Delta H_2+\Delta H_3$

$\Delta H=(+740kJ)+(-240kJ)+(-810kJ)$

$\Delta H=-310kJ$

Therefore, the change in enthalpy of the reaction is, -310 kJ

5 0

3 years ago

When the top right-hand capacitor is filled with a material of dielectric constant κ, the charge on this capacitor is increases

Olin [163]

Answer: k = 2.07692

Explanation: Please find the attached files for the solution

6 0

3 years ago

Read 2 more answers

A plant cell is no longer capable of capturing energy from sunlight and converting it into chemical energy. Which organelle is m

Nadya [2.5K]

The chloroplast of the cell is most likely damaged if the plant cell is no longer capable of capturing energy from sunlight and converting it into chemical energy.

The chloroplast is the structure inside the leaf cell that is known for capturing light energy from the sun.

This light energy is then used to make food that has chemical energy. If a plant cell has a damaged chloroplast or the chloroplast is removed, then it will no longer be able to trap the light energy. As a result, the process of photosynthesis will not occur in the plant cell. The plant cell will not be able to make the chemical energy required for functioning.

To learn more about chloroplast, click here:

brainly.com/question/1741612

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8 0

1 year ago

Convert the arc length of 107869221.61 revolutions into rotation

Genrish500 [490]

Answer:

1 r = 6.283185 rad

677,762,308.31685 rad

Explanation:

8 0

3 years ago