Answer:
a = 603.59 m/s^2
Explanation:
from the data given . the rate of change in magnetic field is as follow
from the faraday's law of induction , the expression for the induced emf in region of radius r as follow
electric field at point P_1 as follow
from newton 2nd law of motion, the acceleration of proton is
F = ma
qE = ma
a = 603.59 m/s^2
Answer:
d. 6.0 m
Explanation:
Given;
initial velocity of the car, u = 7.0 m/s
distance traveled by the car, d = 1.5 m
Assuming the car to be decelerating at a constant rate when the brakes were applied;
v² = u² + 2(-a)s
v² = u² - 2as
where;
v is the final velocity of the car when it stops
0 = u² - 2as
2as = u²
a = u² / 2s
a = (7)² / (2 x 1.5)
a = 16.333 m/s
When the velocity is 14 m/s
v² = u² - 2as
0 = u² - 2as
2as = u²
s = u² / 2a
s = (14)² / (2 x 16.333)
s = 6.0 m
Therefore, If the car had been moving at 14 m/s, it would have traveled 6.0 m before stopping.
The correct option is d
The net charge on an atom is equal to the overall difference between the number of protons in the nucleus versus the number of electrons around the nucleus, where a negative sign represents less protons and a positive sign represents more protons (than electrons).
#8 positive kinetic energy
The frequency of the wave is
Explanation:
The frequency, the wavelength and the speed of a wave are related by the following equation:
where
c is the speed of the wave
f is the frequency
is the wavelength
For the radio wave in this problem,
Therefore, the frequency is:
Learn more about waves here:
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