H = v 0 y 2 2 g . h = v 0 y 2 2 g . This equation defines the maximum height of a projectile above its launch position and it depends only on the vertical component of the initial velocity.
Fnet = ma
4 N = 5 kg * a
a = 4 N/5 kg
a = 0.8 ms^-2
Answer:
625 N
Explanation:
The impulse given to the nail is equal to the change in momentum of the hammer:
where
F is the force exerted by the hammer
is the time of contact
is the mass
is the change in velocity of the hammer
Substituting the data and re-arranging the equation, we can find the force:
Answer:
20 m/s
Explanation:
Height (s)= 20m
acceleration (a) = 10 m/s^2
v=?
we know,
V^2= U^2 + 2as. (U is initial velocity)
or,. V^2 = 0 + 2 × 10 × 20
or, V^2 = 400
or,. V = 20 m/s
Answer:
the missile approaches the second ship at 0.750c. Describe how the ships are moving with respect to one another.
Explanation: