All categories

3 years ago

Which has a greater effect on our tides, the sun or the moon?

Physics

2 answers:

charle [14.2K]3 years ago

7 0

The moon has a greater effect, because it has a gravitational pull also known as gravity.

charle [14.2K]3 years ago

6 0

I’m pretty sure the moon

You might be interested in

A positive charge of 1 µC is taken from points A & B such that VA-VB = 100 V. Then the

Lunna [17]

Explanation:

It is given that,

Let Charge of $1\ \mu C$ is taken from points A & B such that $V_A-V_B=1000\ V$ .

We need to find the energy of charge. Electric potential is defined as the work done per unit of electric charge. So,

$W=(V_B-V_A)q\\\\W=-1000\times 10^{-6}\\\\W=E=-10^{-3}\ J$

So, the energy of charge decreases by $10^{-3}\ J$ . Hence, the correct option is (a).

4 0

3 years ago

A rectangular field is 300 meters long and 300 meters wide. What is the area of the field in square kilometers? Do not round you

dexar [7]

Answer:

Area of the rectangular field in kilometers is 0.09 $km^2$

Explanation:

We know that 1 kilometers = 1000 meters

since we need to find the area in unit of kilometers

therefore converting length and width into kilometers

1000 meters = 1 kilometers

300 meters = $\frac{300}{1000} = 0.3$

Likewise width = 0.3 km

Area = length x width

= 0.3km x 0.3 km

= 0.09 $km^2$

6 0

3 years ago

Why does life be life

Vikentia [17]

Because you don't have your banana milk, broski

8 0

3 years ago

Read 2 more answers

You throw a ball straight up. You are extra strong feeling today. It takes 11 seconds for the ball to come back down.

ollegr [7]

Answer:

A. 148.23 m

B. 2.75 m/s

Explanation:

The following data were obtained from the question:

Time of flight (T) = 11 s

Maximum height (h) =?

Initial velocity (u) =?

Next, we shall determine the time taken for the ball to get to the maximum height. This can be obtained as follow:

Time of flight (T) = 11 s

Time (t) to reach the maximum height =.?

T = 2t

11 = 2t

Divide both side by 2

t = 11/2

t = 5.5 s

NOTE: Time to reach the maximum height is the same as the time taken for the ball to fall back to the plane of projection.

A. Determination of the maximum height to which the ball was thrown.

Time (t) to reach maximum height = 5.5 s

Acceleration due to gravity (g) = 9.8 m/s²

Maximum height (h) =?

h = ½gt²

h = ½ × 9.8 × 5.5²

h = 4.9 × 30.25

h = 148.23 m

B. Determination of the initial velocity.

Maximum height (h) reached = 148.23 m

Acceleration due to gravity (g) = 9.8 m/s²

Initial velocity (u) =?

u² = h/2g

u² = 148.23 / (2 × 9.8)

u² = 148.23 / 19.6

Take the square root of both side

u = √(148.23 / 19.6)

u = 2.75 m/s

5 0

3 years ago

A 30-g bullet is fired with a horizontal velocity of 450 m/s and becomes embedded in block B, which has a mass of 3 kg. After th

Zolol [24]

Answer:

(a) The velocity of the bullet and B after the first impact is 4.4554 m/s.

(b) The velocity of the carrier is 0.40872 m/s.

Explanation:

(a) To solve the question, we apply the principle of conservation of linear momentum as follows.

we note that the distance between B and C is 0.5 m

Then we have

Sum of initial momentum = Sum of final momentum

0.03 kg × 450 m/s = (0.03 kg + 3 kg) × v₂

Therefore v₂ = (13.5 kg·m/s)÷(3.03 kg) = 4.4554 m/s

The velocity of the bullet and B after the first impact = 4.4554 m/s

(b) The velocity of the carrier is given as follows

Therefore from the conservation of linear momentum we also have

(m₁ + m₂)×v₂ = (m₁ + m₂ + m₃)×v₃

Where:

m₃ = Mass of the carrier = 30 kg

Therefore

(3.03 kg)×(4.4554 m/s) = (3.03 kg+30 kg) × v₃

v₃ = (13.5 kg·m/s)÷ (33.03 kg) = 0.40872 m/s

The velocity of the carrier = 0.40872 m/s.

3 0

3 years ago