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olga2289 [7]
3 years ago
8

Why is the formation of ionic compounds exothermic?

Chemistry
1 answer:
bazaltina [42]3 years ago
6 0
TBH i dont know but can you give advice to get more points on this site 


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Akeem cut his finger during an investigation, and it is bleeding slightly. Before helping him bandage the wound,
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b.) Put on protective gloves

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At sea level, a kilogram welghs approximately<br> 2 pounds<br> 10 pounds<br> 5 pounds<br> 1 pound
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1 kilogram weight at sea level would be the equivalent of  2 pounds.

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What is the noble gas electron configuration of bismuth (Bi)? A. [Kr] 6s2 6p3 B. [Xe] 6s2 6p3 C. [Xe] 4f14 5d10 6s2 6p3 D. [Kr]
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Which statement is most consistent with the plum pudding model of the atom?
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The answer to this question would be: <span>1) Electrons occupy regions of space
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In plum pudding model, the atoms are drawn as pudding and the negative particle is spread around the pudding. In this model, the electron is spread but not moving in orbit. Rutherford model that comes afterward is the one that says most of the atoms is empty space.</span>
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3 years ago
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Promethium-147 is sometimes used in luminescent paint. It has a half-life of 956.3 days. If 250 grams (g) of promethium-147 is u
Fantom [35]

Answer:

% = 76.75%

Explanation:

To solve this problem, we just need to use the expressions of half life and it's relation with the concentration or mass of a compound. That expression is the following:

A = A₀ e^(-kt)   (1)

Where:

A and A₀: concentrations or mass of the compounds, (final and initial)

k: constant decay of the compound

t: given time

Now to get the value of k, we should use the following expression:

k = ln2 / t₁/₂   (2)

You should note that this expression is valid when the reaction is of order 1 or first order. In this kind of exercises, we can assume it's a first order because we are not using the isotope for a reaction.

Now, let's calculate k:

k = ln2 / 956.3

k = 7.25x10⁻⁴ d⁻¹

With this value, we just replace it in (1) to get the final mass of the isotope. The given time is 1 year or 365 days so:

A = 250 e^(-7.25x10⁻⁴ * 365)

A = 250 e^(-0.7675)

A = 191.87 g

However, the question is the percentage left after 1 year so:

% = (191.87 / 250) * 100

<h2>% = 76.75%</h2><h2>And this is the % of isotope after 1 year</h2>
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