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Anton [14]
3 years ago
13

You are a scientist conducting an experiment on energy transfers. During the reaction you measure a large transfer of heat energ

y. What units should you record them in? A. Joules B. Degrees Celsius C. Volts D. Degrees Kelvin
Chemistry
2 answers:
Ainat [17]3 years ago
8 0

Answer:

Option A is true

Explanation:

When you are a scientist conducting an experiment on energy transfer .

The reaction in which you measure a large amount of heat energy transfer.

We have to find the units which you should record them in

Energy: It is defined as the capability of doing the work .

When current I is flowing in ampere A  V is potential in volt  v applied  in the experiment  and R be resistance  in ohm used in experiment for time t in seconds

Then, heat energy =VI=A-volt=Joule

Heat energy=I^2Rt

Heat energy=A^2ohm sec=Joule

The S.I unit of heat energy is Joules.

Hence, option A is true.

Luda [366]3 years ago
5 0

Answer:

Joules

Explanation:

The another ones are units of tempeture (B and D) and unit of electricity that relatione energy and charge. In chemistry the energy es measured in Joules, because the energy is  work done on an object when a force of one newton acts on that object in the direction of the force's motion through a distance of one metre. In other words, J=Nm

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What is the limiting reagent when a 2.00 g sample of ammonia is mixed with 4.00 g of oxygen?​
UNO [17]

Answer:

Ammonia is limiting reactant

Amount of oxygen left  = 0.035 mol

Explanation:

Masa of ammonia = 2.00 g

Mass of oxygen = 4.00 g

Which is limiting reactant = ?

Balance chemical equation:

4NH₃ + 3O₂     →     2N₂ + 6H₂O

Number of moles of ammonia:

Number of moles = mass/molar mass

Number of moles = 2.00 g/ 17 g/mol

Number of moles = 0.12 mol

Number of moles of oxygen:

Number of moles = mass/molar mass

Number of moles = 4.00 g/ 32 g/mol

Number of moles = 0.125 mol

Now we will compare the moles of ammonia and oxygen with water and nitrogen.

                      NH₃          :            N₂

                        4             :             2

                      0.12           :           2/4×0.12 = 0.06

                      NH₃         :            H₂O

                        4            :             6

                        0.12       :           6/4×0.12 = 0.18

                       

                       O₂            :            N₂

                        3             :             2

                      0.125        :           2/3×0.125 = 0.08

                        O₂           :            H₂O

                        3              :             6

                        0.125       :           6/3×0.125 = 0.25

The number of moles of water and nitrogen formed by ammonia are less thus ammonia will be limiting reactant.

Amount of oxygen left:

                        NH₃          :             O₂

                           4            :              3

                           0.12       :          3/4×0.12= 0.09

Amount of oxygen react = 0.09 mol

Amount of oxygen left  = 0.125 - 0.09 = 0.035 mol

3 0
3 years ago
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