Answer:
14.7838
Explanation:
Given that;
A student uses a solution that contains 16 g of water to conduct an experiment and at the end of an hour ; the amount have decreased by 3.5%
The mathematically illustration for this is given as
= 16 g × 3.5%
= 
= 0.56
After an hour; the amount have decreased by 16 - 0.56
= 15.44
after 2 hours the water decreased by another 4.25%
i.e 
⇒ 0.6562
after two hours , the amount would have decreased by:
= 15.44 - 0.6562
= 14.7838
Answer:
Hydrogen = 2.5 * 10^21
Explanation:
Chemical Formula Glucose: C₆H₁₂O₆
One of the ways you could do this is to notice that for every carbon atom there are two Hydrogen atoms. You can state this more formally by using the formula to set up a ratio: 12/6 = hydrogen to Carbon
So if there are 1.250 * 10^21 Carbon atoms in the Glucose sample, then there will be twice as many hydrogen atoms.
H = 2 * 1.25 * 10^21 = 2.5 * 10^21 atoms
You could do this more formally by setting up a proportion.
6 Carbon / 12 Hydrogen = 1.25*10^21 / x Cross Multiply
6*x = 12 * 1.25*10^21 Combine the right
6x = 1.5 * 10^22 Divide by 6
x = 2.5 * 10^21
Answer:
Explanation:
use the equation
moles = mass/mr
=19.9/79.5
=0.250moles of CuO
then do the same for
H = 2.02/1
=2.02
so CuO is the limiting reagent because there is less amount of it.
Hope this helps :)
Yes, depending on the thickness.
Ca(OH)₂: strong base
pOH = a . M
a = valence ( amount of OH⁻)
M = concentration
Ca(OH)₂ ⇒ Ca²⁺ + 2OH⁻ (2 valence)
so:
pOH = 2 x 0.005
pOH = 0.01
pH = 14 - 0.01 = 13.99
