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Maslowich
3 years ago
13

The equilibrium system Co(H2O)62+ + 4Cl– ⇌ CoCl42– + 6H2O is endothermic as written, meaning heat is a reactant for the forward

reaction and a product for the reverse reaction. Based on that information and your findings from this experiment, predict what you would expect to observe in the experiment you described above when you tested the effects of temperature on an equilibrium position.
Chemistry
1 answer:
kozerog [31]3 years ago
5 0

Answer:

  1. Increasing the temperature: shifts the equilibrium to the products side (towards the right direction).
  2. Decreasing the temperature: shifts the equilibrium to the reactants (towards the left direction).

Explanation:

Le Châtelier's principle states that when there is an dynamic equilibrium, and this equilibrium is disturbed by an external factor, the equilibrium will be shifted in the direction that can cancel the effect of the external factor to reattain the equilibrium.

For the mentioned endothermic reaction can be represented as:

Co(H₂O)₆²⁺ + 4Cl⁻ + heat ⇌ CoCl₄²⁻ + 6H₂O.

In endothermic reactions: heat is a reactant for the forward reaction and a product for the reverse reaction.

So the effect of temperature on the equilibrium position is:

  • Increasing the temperature:

Increasing the temperature leads to increasing the concentration of the reactants, so the equilibrium will be shifted to the products side (towards the right direction) to suppress the effect of increasing T.

  • Decreasing the temperature:

Decreasing the temperature leads to decreasing the concentration of the reactants, so the equilibrium will be shifted to the reactants (towards the left direction) to suppress the effect of decreasing T.

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The decomposition of dinitrogen pentoxide, N2O5, to NO2 and O2 is a first-order reaction. At 60°C, the rate constant is 2.8 × 10
Sati [7]

Answer:

a. 113 min

Explanation:

Considering the equilibrium:-

                   2N₂O₅ ⇔ 4NO₂ + O₂

At t = 0        125 kPa

At t = teq     125 - 2x      4x        x

Thus, total pressure = 125 - 2x + 4x + x = 125 - 3x

125 - 3x = 176 kPa

x = 17 kPa

Remaining pressure of N₂O₅ = 125 - 2*17 kPa = 91 kPa

Using integrated rate law for first order kinetics as:

[A_t]=[A_0]e^{-kt}

Where,  

[A_t] is the concentration at time t

[A_0] is the initial concentration

Given that:

The rate constant, k = 2.8\times 10^{-3} min⁻¹

Initial concentration [A_0] = 125 kPa

Final concentration [A_t] = 91 kPa

Time = ?

Applying in the above equation, we get that:-

91=125e^{-2.8\times 10^{-3}\times t}

125e^{-2.8\times \:10^{-3}t}=91

-2.8\times \:10^{-3}t=\ln \left(\frac{91}{125}\right)

t=113\ min

3 0
3 years ago
In at least three sentences, explain three disadvantages associated with hydrogen fuel use.
Dmitry_Shevchenko [17]

Here are some disadvantages, is that nitrogen dioxide is a toxic gas and it can still be harmful when ingested by human, also critics of hydrogen fuel cells argue that although these cells do not emit carbon after burning, they give out nitrogen dioxide and other emissions.

Hope this helps

7 0
3 years ago
slader An experiment is carried out where 13.9 g of solid NaOH is dissolved in 250.0 g of water in a coffee-cup calorimeter. Dis
kvv77 [185]

Answer:

The mass of the surrounding is M_t = 263.9 \ g

Explanation:

From the question we are told that

      The mass of  NaOH is  m = 13.9 \ g

      The mass of water is m_w = 250.0g

      The chemical equation for the dissociation process is

       NaOH _{(s) } ---> Na^{+}_{(aq)} + OH^{-} _{(aq)}

       The specific heat capacity of the mixture is c_p = 4.18 J g^{-1} C^{-1}

       

The combined mass of the solution is

         M_t = 13 + 250

         M_t = 263.9 \ g

The mass of the surround here is the mass of the coffee-cup calorimeter and this contain the mixture ( water and the NaOH ) so the mass of the surrounding is  

  M_t = 263.9 \ g

       

3 0
3 years ago
There are two steps in the usual industrial preparation of acrylic acid, the immediate precursor of several useful plastics. In
KIM [24]

Answer:

ΔH = -470.4kJ

Explanation:

It is possible to sum 2 or more reactions to obtain the ΔH of the reaction you want to study (Hess's law). Using the reactions:

1. CaC2(s) + 2H2O(l) → C2H2(g) + Ca(OH)2(s)ΔH = −414kJ

2. 6C2H2(g) + 3CO2(g) + 4H2O(g) → 5CH2CHCO2H(g)ΔH = 132kJ

6 times the reaction 1.

6CaC2(s) + 12H2O(l) → 6C2H2(g) + 6Ca(OH)2(s)ΔH = −414kJ*6 = -2484kJ

This reaction + 2:

6CaC2(s) + 3CO2(g) + 16H2O(l) →  + 6Ca(OH)2(s) + 5CH2CHCO2H(g) ΔH = -2484kJ + 132kJ = -2352kJ

As we want to calculate the net change enthalpy in the formation of just 1 mole of acrylic acid we need to divide this last reaction in 5:

6/5CaC2(s) + 3/5CO2(g) + 16/5H2O(l) →  + 6/5Ca(OH)2(s) + CH2CHCO2H(g) ΔH = -2352kJ / 5

<h3>ΔH = -470.4kJ</h3>

4 0
3 years ago
What is the formula, when rubidium reacts with tellurium?
natita [175]

Answer:

Like other alkali metals, rubidium metal reacts violently with water. As with potassium (which is slightly less reactive) and caesium (which is slightly more reactive), this reaction is usually vigorous enough to ignite the hydrogen gas it produces.

Explanation:

hope it helps

5 0
3 years ago
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