Answer:
tide
Explanation:
A tide is when the moon reactes to the moon is caused gravity to make the tide moves
Answer : The experimental density of liquid X is, 0.79 g/ml
Solution : Given,
Mass of an empty graduated cylinder = 27.3 g
Mass of cylinder and mass of liquid X = 35.2 g
Volume of liquid X = 10 ml
First we have to calculate the mass of liquid X.
Mass of cylinder + Mass of liquid X = 35.2 g
Mass of liquid X = 35.2 g - Mass of cylinder
Mass of liquid X = 35.2 g - 27.3 g = 7.9 g
Now we have to calculate the density of liquid X.
Formula used for density :
Now put all the given values in this formula, we get the density of liquid X.
Therefore, the experimental density of liquid X is, 0.79 g/ml
C - one single type of atom
A) is 6.49
b) is 6.28
c) is 9.77
d) ph is 11.77
Answer : The oxidation state of Mg in Mg(s) is (0).
Explanation :
Oxidation number or oxidation state : It represent the number of electrons lost or gained by the atoms of an element in a compound.
Oxidation numbers are generally written with the sign (+) and (-) first and then the magnitude.
Rules for Oxidation Numbers are :
The oxidation number of a free element is always zero.
The oxidation number of a monatomic ion equals the charge of the ion.
The oxidation number of Hydrogen (H) is +1, but it is -1 in when combined with less electronegative elements.
The oxidation number of oxygen (O) in compounds is usually -2.
The oxidation number of a Group 17 element in a binary compound is -1.
The sum of the oxidation numbers of all of the atoms in a neutral compound is zero.
The sum of the oxidation numbers in a polyatomic ion is equal to the charge of the ion.
The given chemical reaction is:
In the given reaction, the oxidation state of Mg in Mg(s) is (0) because it is a free element and the oxidation state of Mg in is (+2).
Hence, the oxidation state of Mg in Mg(s) is (0).