Answer:
a) 17.086m
b) 0.1671 m
Explanation:
Given data: speed of water through the hose  = 1.81 m/s
through the nozzle = 18.3 m/s
We know that maximum height of an object with upward velocity v is given by,
a) H = v^2/2g
where H is the maximum height water emerges  
= 18.3^2/(2×9.8) = 17.086 m answer
b) Again,  
 H = v^2/2g
= 1.81^2/(2×9.8) = 0.1671 m
 
        
             
        
        
        
Answer:
Explanation:
  For entry of light into tube of unknown refractive index 
sin ( 90 - 25 ) / sinr = μ , μ is the refractive index of the tube , r is angle of refraction in the medium of tube 
r = 90 - C where C is critical angle between μ and body medium in which tube will be inserted. 
sin ( 90 - 25 ) / sin( 90 - C)  = μ
sin65 / cos C = μ
sinC = 1.33 / μ  , where 1.33 is the refractive index of body liquid. 
From these equations
sin65 / cos C = 1.33 / sinC 
TanC = 1.33 / sin65
TanC = 1.33 / .9063
TanC = 1.4675
C= 56°
sinC = 1.33 / μ
 μ = 1.33 / sinC
= 1.33 / sin56
= 1.33 / .829
μ = 1.6   Ans 
 
        
             
        
        
        
Do you not understand how to solve for the answer?
        
             
        
        
        
Answer:
distance and time
Explanation: the farther you go and how much time it will take you