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Gnom [1K]
3 years ago
13

Quick I need help.....

Mathematics
2 answers:
marin [14]3 years ago
6 0
The third one x>_ -4
Vitek1552 [10]3 years ago
3 0

Answer:

C

Step-by-step explanation:

Subtract both sides by 2

2-2 is 0

-10 - 2 is 12

-3x < 12

Divide both sides by -3

Switch signs cause dividing a negative

x > -4

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Brainpop estimating quiz answers PLZ HELP NOW PLZ NOW HELP PLZ ALL ANSWERS PLZ HELP
expeople1 [14]

Answer:

with what

Step-by-step explanation:

8 0
3 years ago
Evaluate f(x) = 2x +3 for f(4)<br> a-11<br> b-8<br> c-4<br> d-3
Scrat [10]

Answer:

the answer is a-11

Step-by-step explanation:

f(x)=2x+3

f(4)=2(4)+3

f(4)=8+3

f(4)=11

5 0
3 years ago
What is the value of x? 6(-3-x)-2x=14
Lera25 [3.4K]
The equation given in the question has one unknown variable in the form of "x" and only one equation is required to find the value of the unknown variable. So it is absolutely possible to find the exact value of "x".
6(-3 - x) - 2x = 14
-18 - 6x - 2x = 14
-18 - 8x = 14
Multiplying both sides of the equation by -1 we get
8x + 18 = - 14
Dividing both sides by 2 we get
4x + 9 = - 7
4x = - 7 - 9
4x = - 16
x = - 16/4
  = - 4
So the value of "x" comes out to be equal to - 4. I hope the procedure is clear enough for you to understand.
7 0
3 years ago
Read 2 more answers
Janell has a 10 inch by 12 inch photograph. She wants to scan the photograph
Dmitry_Shevchenko [17]

<u>Complete Question:</u>

Janeel has a 10 inch by 12 inch photograph. She wants to scan the photograph, then reduce the results by the same amount in each dimension to post on her Web site. Janeel wants the area of the image to be one eight of the original photograph. Write an equation to represent the area of the reduced image. Find the dimensions of the reduced image.

<u>Correct Answer:</u>

A) (10-x)(12-x)=15

B) Dimensions are : Length = 10-x = 3 inch , Breadth = 12-x = 5 inch

<u>Step-by-step explanation:</u>

a. Write an equation to represent the area of the reduced image.

Let the reduced dimensions is by x , So the new dimensions are

length=10-x\\breadth=12-x

According to question , Area of new image is :

⇒ Area = \frac{1}{8}Length(breadth)

⇒ Area = \frac{1}{8}(10)(12)

⇒ Area = 15

So the equation will be :

⇒ (10-x)(12-x)=15

b. Find the dimensions of the reduced image

Let's solve :  (10-x)(12-x)=15

⇒ 120-10x-12x+x^2=15

⇒ 120-22x+x^2=15

⇒ x^2-22x+105=0

By Quadratic formula :

⇒ x = \frac{-b \pm \sqrt{b^2-4ac} }{2a}

⇒ x = \frac{22 \pm8 }{2}

⇒ x = \frac{22 +8 }{2} , x = \frac{22 -8 }{2}

⇒ x = 15 , x =7

x = 15 is rejected ! as 15 > 10 ! Side can't be negative

⇒ x =7

Therefore, Dimensions are : Length = 10-x = 3 inch , Breadth = 12-x = 5 inch

7 0
3 years ago
Find two numbers that meet the requirements of the situation in each question. Put the smaller of the two numbers in the first b
Gwar [14]

Answer:

-8, 8 are the numbers

Step-by-step explanation:

8x-8 = -64

8+ -8 =0

5 0
3 years ago
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