Answers:(a) 
μT
(b) 
μm
(c) f =
Explanation:Given electric field(in y direction) equation:

(a) The amplitude of electric field is

. Hence
The amplitude of magnetic field oscillations is

Where c = speed of light
Therefore,

μT (Where T is in seconds--signifies the oscillations)
(b) To find the wavelength use:



μm
(c) Since c = fλ
=> f = c/λ
Now plug-in the values
f = (3*10^8)/(0.4488*10^-6)
f =
Answer:
D, using a spring scale to exert a force on the block. Measure the acceleration of the block and the applied force
Explanation:
For this you would use the net force equation acceleration=net force * mass however you will want to isolate mass so it would be acceleration/ net force to get mass. Then process of elimination comes to play.
Answer:
confounding cause they had exposure to many programmes
Answer:
289282
Explanation:
r = Radius of plate = 0.52 mm
d = Plate separation = 0.013 mm
A = Area = 
V = Potential applied = 2 mV
k = Dielectric constant = 40
= Electric constant = 
Capacitance is given by

Charge is given by

Number of electron is given by

The number of charge carriers that will accumulate on this capacitor is approximately 289282.
Answer:
3.192 m/s
Explanation:
t = Time taken = 0.900 seconds
u = Initial velocity
v = Final velocity
s = Displacement = 1.1 meters
a = Acceleration due to gravity = 9.81 m/s²

Velocity of the elevator when it snapped is 3.192 m/s