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3 years ago

ASAP ONLY ACTUAL CORRECT ANSWERS

Physics

2 answers:

fredd [130]3 years ago

8 0

Answer:

The correct option is A) I. The seasons change throughout the year

Explanation:

The Earth tilts around its axis which causes the Northern and Southern hemisphere of the Earth to switch places throughout the year. This causes the hemispheres to have alternate times in facing the Sun at a particular time. This causes the season to change in each part of the Earth. For example, when the Northern Hemisphere faces the Sun, summers will arise in the Norther hemisphere where as the Southern hemisphere will be away from the sun and have winter.

The tilt of the Earth is known to be at an angle of 23.5 degrees.

11111nata11111 [884]3 years ago

8 0

Answer: C) I and III only

Explanation: The tilt of the Earth's axis, combined with the Earth's orbit around the Sun, results in the changes in seasons throughout the year.

It also causes daytime (the number of hours of daylight) to be longer than nighttime during the summer than during the winter.

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Allushta [10]

Answer:

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Which of these is the easiest mineral identification property to use when you want to know whether you have pyrite or actual gol

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c. streak

Explanation:

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3 years ago

A 5-mm-thick stainless steel strip (k = 21 W/m·K, rho = 8000 kg/m3, and cp = 570 J/kg·K) is being heat treated as it moves throu

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3 years ago

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Write in the word "stronger" or "weaker." The bigger and

SVETLANKA909090 [29]

Answer:

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3 years ago

8. An unpowered flywheel is slowed by a constant frictional torque. At time t = 0 it has an angular velocity of 200 rad/s. Ten s

allsm [11]

Answer:

a) $\omega = 50\,\frac{rad}{s}$ , b) $\omega = 0\,\frac{rad}{s}$

Explanation:

The magnitude of torque is a form of moment, that is, a product of force and lever arm (distance), and force is the product of mass and acceleration for rotating systems with constant mass. That is:

$\tau = F \cdot r$

$\tau = m\cdot a \cdot r$

$\tau = m \cdot \alpha \cdot r^{2}$

Where $\alpha$ is the angular acceleration, which is constant as torque is constant. Angular deceleration experimented by the unpowered flywheel is:

$\alpha = \frac{170\,\frac{rad}{s} - 200\,\frac{rad}{s} }{10\,s}$

$\alpha = -3\,\frac{rad}{s^{2}}$

Now, angular velocities of the unpowered flywheel at 50 seconds and 100 seconds are, respectively:

a) t = 50 s.

$\omega = 200\,\frac{rad}{s} - \left(3\,\frac{rad}{s^{2}} \right) \cdot (50\,s)$

$\omega = 50\,\frac{rad}{s}$

b) t = 100 s.

Given that friction is of reactive nature. Frictional torque works on the unpowered flywheel until angular velocity is reduced to zero, whose instant is:

$t = \frac{0\,\frac{rad}{s}-200\,\frac{rad}{s} }{\left(-3\,\frac{rad}{s^{2}} \right)}$

$t = 66.667\,s$

Since $t > 66.667\,s$ , then the angular velocity is equal to zero. Therefore:

$\omega = 0\,\frac{rad}{s}$

7 0

3 years ago