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Wittaler [7]
3 years ago
15

8. A book is pushed a distance of 0.78 m by a force that gives the book an acceleration of 1.54 m/s². If 1.56 J of work is done

on the book, what is the book’s mass?
Physics
1 answer:
kozerog [31]3 years ago
6 0

Answer:

1.29 kg

Explanation:

As we know that

W= FS

1.56 = F (0.78)

F= 1.56/0.78

F= 2 N

Now, According to the definition of Force

F= ma

then

m= F /a

m= 2 / 1.54

m = 1.29 kg

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How can a force change the motion of an object that is already moving?
lara [203]

Answer:They may cause motion to change

Explanation:They may cause motion; they may also slow, stop, or change the direction of motion of an object that is already moving. Since force cause changes in the speed or direction of an object, we can say that forces cause changes in velocity. Remember that acceleration is a change in velocity.

7 0
3 years ago
The place kicker on a football team kicks a ball from ground level with an initial speed of 5.80 m/s at an angle of 17.0° above
Likurg_2 [28]

Answer:

0.34 s

Explanation:

Given that,

Initial speed of a ball, u = 5.8 m/s

It is kicked at an angle of 17.0° above the horizontal.

The vertical component of velocity will be,

u_y=u\sin\theta\\\\=5.8\times \sin 17\\\\=1.69\ m/s

Let it takes t time in the air before it lands on the ground again. It can calculated as :

t=\dfrac{2u_y}{g}\\\\t=\dfrac{2\times 1.69}{9.8}\\\\t=0.34\ s

So, it will take 0.34 seconds.

8 0
3 years ago
A chemical ________ involves one or more reactants changing into new products.
kaheart [24]
Reaction is the answer. If you're wondering why, all you need to do is look up the definitions of the words.
6 0
3 years ago
You push your couch a distance of 3.9 m across the living room floor with a horizontal force of 220.0 n. the force of friction i
Mrac [35]

The general formula to calculate the work is:

W=Fd \cos \theta

where F is the force, d is the displacement of the couch, and \theta is the angle between the direction of the force and the displacement. Let's apply this formula to the different parts of the problem.


(a) Work done by you: in this case, the force applied is parallel to the displacement of the couch, so \theta=0^{\circ} and \cos \theta=1, therefore the work is just equal to the product between the horizontal force you apply to push the couch and the distance the couch has been moved:

W=Fd=(220.0 N)(3.9 m)=858 J


(b) work done by the frictional force: the frictional force has opposite direction to the displacement, therefore \theta=180^{\circ} and \cos \theta=-1. Therefore, we must include a negative sign when we calculate the work done by the frictional force:

W=-Fd=-(144.0 N)(3.9 m)=-561.6 J


(c) The work done by gravity is zero. In fact, gravity (which points downwards) is perpendicular to the displacement of the couch (which is horizontal), therefore \theta=90^{\circ} and \cos \theta=0: this means

W=0.


(d) Work done by the net force:

The net force is the difference between the horizontal force applied by you and the frictional force:

F=220 N-144 N=76 N

And the net force is in the same direction of the displacement, so \theta=0^{\circ} and \cos \theta=1 and the work done is

W=Fd=(76 N)(3.9 m)=296.4 J


4 0
3 years ago
A sample of water is heated at a constant pressure of one atmosphere. Initially, the sample is ice at 260 K, and at the end the
USPshnik [31]

In <u>370 K to 375 K </u>temperature intervals of 5 K, would be the greatest increase in the entropy of the sample.

Option: C

<u>Explanation</u>:

Because the largest difference in molar entropy occurs when a condensed phase (solid/liquid) transforms to the gas phase. Then change in entropy is equal to heat transfer divided by temperature: \Delta \mathrm{S}=\frac{\Delta Q}{\mathrm{m} T}.

According to given ice sample at 260 K, when this solid sample start converting into liquid sample it will gain positive temperature and steam will take place near 373 K (273 K ice temperature + 100^{\circ} \mathrm{C} temperature of boiling water). Therefore it’s very obvious that greatest increase in entropy will occur during 370 K – 375 K.

5 0
3 years ago
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