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4 years ago

Newton’s second law of motion addresses the relationship between what two variables that influence the force on a body?

2 answers:

8 0

Newton’s Second Law concerns the generation of force based on an object’s mass and acceleration, as described by the equation F=ma.

Hope this helps!

Ronch [10]4 years ago

5 0

The two variables which influences the body force addressed in “Newton’s second law of motion” s mass and acceleration.

<u>Explanation:</u>

The “Newton’s second law of motion” states that rate of change of momentum is directly in proportional to force applied on body.

$\begin{array}{l}{F \propto \frac{d p}{d t}} \\ {F=m \cdot \frac{d v}{d t}} \\ {F=m \cdot a} \\ {\text { Force }=\text {Mass} \times \text {Acceleration}}\end{array}$

This is how the Second law of motion is derived in formula by the Newton which establishes the relationship between the two variables which influences the force of the body.

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Determine a formula for the magnitude of the force F exerted on the large block (Mc) so that the mass Ma does not move relative

SVEN [57.7K]

Answer:

The magnitude of the force F is given by

F = ( $M_{a}$ + $M_{b}$ + $M_{c}$ ) *( $M_{b}$ *g/( $\sqrt{M_{a} ^{2}-M_{b} ^{2}}$ ))

Explanation:

Given there are three blocks of masses $M_{a}$ , $M_{b}$ and $M_{c}$ (ref image in attachment)

When all three masses move together at an acceleration a, the force F is given by

F = ( $M_{a}$ + $M_{b}$ + $M_{c}$ ) *a ................(equation 1)

Also it is given that $M_{a}$ does not move with respect to $M_{c}$ , which gives tension T is exerted on pulley by $M_{a}$ only, Hence tension T is

T = $M_{a}$ *a ..........(equation 2)

There is also also tension exerted by $M_{b}$ . There are two components here: horizontal due to acceleration a and vertical component due to gravity g. Thus tension is given by

T = $M_{b}$ $\sqrt{a^{2} +g^{2} }$ ................(equation 3)

From equation 2 and 3, we get

$M_{a}$ *a = $M_{b}$ $\sqrt{a^{2} +g^{2} }$

Squaring both sides we get

$M_{a} ^{2}$ * $a^{2}$ = $M_{b} ^{2}$ * ( $a^{2}$ + $g^{2}$ )

$M_{a} ^{2}$ * $a^{2}$ = ( $M_{b} ^{2}$ * $a^{2}$ )+ ( $M_{b} ^{2}$ * $g^{2}$ )

( $M_{a} ^{2}$ - $M_{b} ^{2}$ ) * $a^{2}$ = $M_{b} ^{2}$ * $g^{2}$

$a^{2}$ = $M_{b} ^{2}$ * $g^{2}$ /( $M_{a} ^{2}$ - $M_{b} ^{2}$ )

Taking square root on both sides, we get acceleration a

a = $M_{b}$ *g/( $\sqrt{M_{a} ^{2}-M_{b} ^{2}}$ )

Hence substituting the value of a in equation 1, we get

F = ( $M_{a}$ + $M_{b}$ + $M_{c}$ ) *( $M_{b}$ *g/( $\sqrt{M_{a} ^{2}-M_{b} ^{2}}$ ))

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3 years ago

Define average velocity <br>

maxonik [38]

Hello! mark me brainliest please

The average speed of an object is defined as the distance traveled divided by the time elapsed. Velocity is a vector quantity, and average velocity can be defined as the displacement divided by the time.

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3 years ago

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True or false? An object at rest has an instantaneous acceleration of zero.

Tpy6a [65]

True. it’s at rest which means it’s not moving so there’s no acceleration

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3 years ago

if the forces are moving in the same direction, ____ the forces. Please help i’m actually so confused!

jasenka [17]

Answer:

Explanation:

the directions may change

Or they will repel and become opposite sides

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