Answer:
Double time = 65.42 years
Explanation:
We can find what year the human population would double using the rule of 70. This is given as;
Double time = 70 / rate(r)
From the question;
Double time = ?
Rate = 1.07%
Inserting into the equation;
Double time = 70 / 1.07
Double time = 65.42 years
On average, seawater in the world's oceans has a salinity of ~3.5%. This means that for every 1 litre (1000 mL) of seawater there are 35 grams of salts (mostly, but not entirely, sodium chloride) dissolved in it.
<h3>What is salinity ?</h3>
The saltiness or quantity of dissolved salt in a body of water is known as salinity (see also soil salinity). The standard units of measurement are grams of salt per liter (g/L) or grams per kilogram (g/kg; the latter is dimensionless and equal to ).
Salinity is a thermodynamic state variable that, along with temperature and pressure, controls physical properties like the density and heat capacity of the water. Salinity plays a significant role in determining many aspects of the chemistry of natural waters and of biological processes within them.
An isohaline, or isohale sometimes, is a contour line with a constant salinity.
The concept of salinity in rivers, lakes, and the ocean is straightforward, but it is difficult to define and measure properly on a scientific level.
To learn more about salinity from the given link:
brainly.com/question/3074395
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Use this: https://quizlet.com/94519197/bio-ch1-flash-cards/ , it may help
The correct equilibrium expression would be one that has products over reactants, and to the power of their stoichiometric coefficient. Also, it would not include any liquids or solids.
The equilibrium expression for your balanced reaction is:
![\Large K_c = \sf{\frac{[SO_3]^2_{equil}}{[SO_2]^2_{equil}[O_2]^2_{equil}}](https://tex.z-dn.net/?f=%5CLarge%20K_c%20%3D%20%5Csf%7B%5Cfrac%7B%5BSO_3%5D%5E2_%7Bequil%7D%7D%7B%5BSO_2%5D%5E2_%7Bequil%7D%5BO_2%5D%5E2_%7Bequil%7D%7D)
Answer : The initial concentration of HI and concentration of 
at equilibrium is, 0.27 M and 0.386 M respectively.
Solution : Given,
Initial concentration of 
and 
= 0.11 M
Concentration of and at equilibrium = 0.052 M
Let the initial concentration of HI be, C
The given equilibrium reaction is,
Initially 0.11 0.11 C
At equilibrium (0.11-x) (0.11-x) (C+2x)
As we are given that:
Concentration of and at equilibrium = 0.052 M = (0.11-x)
0.11 - x = 0.052
x = 0.11 - 0.052
x = 0.058 M
The expression of 
will be,
![K_c=\frac{[HI]^2}{[H_2][I_2]}](https://tex.z-dn.net/?f=K_c%3D%5Cfrac%7B%5BHI%5D%5E2%7D%7B%5BH_2%5D%5BI_2%5D%7D)
By solving the terms, we get:
C = 0.27 M
Thus, initial concentration of HI = C = 0.27 M
Thus, the concentration of at equilibrium = (C+2x) = 0.27 + 2(0.058) = 0.386 M
