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3 years ago

Where are fusion reactions found

Chemistry

2 answers:

Paha777 [63]3 years ago

4 0

Answer:

In a nuclear fusion reaction, the nuclei of two atoms combine to create a new atom. Most commonly, in the core of a star, two hydrogen atoms fuse to become a helium atom. Although nuclear fusion reactions require a lot of energy to get started, once they are going they produce enormous amounts of energy.

Explanation:

ankoles [38]3 years ago

3 0

It’s usually in the core of a star. When two hydrogen atoms fuse to become a helium atom

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Set up the ion formation equations, with ionization energy values for each electron in the valence layer, of the atoms of the ch

Studentka2010 [4]

Explanation:

Set up the ion formation equations, with ionization energy values for each electron in the valence layer, of the atoms of the chemical elements below: a) Na z=11 b) Ca z= 20 c) Sr z 38 d) Li z= 3 e) Cs z= 55 f) Be z= 43

7 0

3 years ago

If 980kJ of energy as heat are transferred to 6.2L of water at 291 K what will the final temperature be? The specific heat of wa

In-s [12.5K]

Answer:

Final temperature = T₂ = 328.815 K

Explanation:

Given data:

Given energy = 980 KJ = 980×1000= 980000 J

Volume = 6.2 L

Initial temperature =T₁= 291 K

Specific heat of water = 4.18 j /g .K

Final temperature = T₂ = ?

Formula:

Q = m. c . ΔT

ΔT = T₂ - T₁

we will first convert the litter into milliliter

6.2 × 1000 = 6200 mL

It is given in question that

1 mL = 1 g

6200 mL = 6200 g

Now we will put the values in formula,

Q = m. c . (T₂ - T₁)

980000 j = 6200 g . 4.18 j /g .K . (T₂ - 291 K)

980000 j = 25916 j/ k . (T₂ - 291 K)

980000 j / 25916 j/ k = T₂ - 291 K

37.8145 K + 291 K =T₂

T₂ = 328.815 K

4 0

4 years ago

Calculate the specific heat capacity of a piece of ice if 1.30 kg of the wood absorbs 6.75×104 joules of heat, and its temperatu

spayn [35]

Answer:

1.8 J/ g ∘ C

Explanation:

A substance's specific heat tells you how much heat much either be added or removed from 1 g of that substance in order to cause a 1 ∘ C change in temperature.

The equation that establishes a relationship between specific heat, heat added or removed.

8 0

4 years ago

Read 2 more answers

Calculate the solubility at 25°c of cubr in pure water and in a 0.0030m cobr2 solution. you'll find ksp data in the aleks data t

Reil [10]

Answer:

the solubility at 25°c of cubr in pure water = 0.011 g/L

The solubility at 25°c of cubr in a 0.0030m cobr2 solution = 0.00014 g/L

Explanation:

Step 1: Data given

Ksp of CuBr = 6.27 × 10^-9

Molar mass CuBr = 143.45 g/mol

Step 2: Calculate the solubility at 25°c of cubr in pure water

Ksp = [Cu+][Br-]

The initial concentration

[Cu+] = 0M

[Br-] = 0M

The concentration at the equilibrium

[Cu+] = X M

[Br-] = X M

Ksp =6.27 * 10^-9 = X * X = X²

S = 7.9 *10^-5 mol /l

7.9 * 10^-5 mol/L * 143.45 g/mol = 0.011 g/L

Step 3: Calculate the solubility at 25°c of cubr in a 0.0030m cobr2 solution.

The balanced equation:

CoBr2(aq) → Co^2+(aq) + 2 Br⁻(aq)

For 1 mol CoBr2 we'll have 1 mol Co^2+ and 2 moles Br-

For 0.0030 M CoBr2 we'll have 0.0030 M Co^2+ and 0.0060 M Br-

The initial concentration

[Cu+] = 0M

[Br-] = 0.0060 M

At the equilibrium

[Cu+] = X

[Br-] = 0.0060 + X

Ksp = 6.27 * 10^-9 = X * (0.0060+X)

6.27 *10^-9 = 0.0060 X + X²

X = 1.0 * 10^-6 mol/L

1.0 * 10^-6 mol/L * 143.45 g/mol = 0.00014 g/L

6 0

3 years ago

How many milliliters o a suspension base must be mixed with 250 mL o a paroxetine (PAXIL) oral suspension, 10 mg/5 mL, to change

Maksim231197 [3]

Answer : The suspension base added will be, 250 mL

Explanation :

As we are given that the initial concentration of solution is, 10 mg/5mL or we can say that 2 mg/mL.

Volume of solution = 250 mL

First we have to determine the mass of PAXIL.

As, 1 mL of solution contain mass of PAXIL = 2 mg

So, 250 mL of solution contain mass of PAXIL = $250\times 2=500mg$

Now we have to determine the final solution required.

As we are given the final concentration of solution is, 0.1 % w/v that means 0.1 g in 100 mL of solution.

Concentration of solution = $\frac{0.1g}{100mL}=\frac{0.1\times 1000mg}{100mL}=\frac{100mg}{100mL}=\frac{1mg}{mL}$

Let the 'x' mL of the suspension base is added. So, the ratio of mass and volume will be:

$\frac{500mg}{(x+250)mL}=\frac{1mg}{1mL}$

$x=250mL$

Thus, the suspension base added will be, 250 mL

4 0

3 years ago