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Gala2k [10]
3 years ago
13

Multiply 2 cm by 100 to convert to meters​

Physics
1 answer:
zavuch27 [327]3 years ago
5 0

Answer:

1m= 100cm

?= 2cm let ? be (n)

cross multiply

100n = 2

n= 2÷100

n= 0.02m

therefore 2cm is equal to 0.02 m

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6 0
2 years ago
A tennis player swings and hits the ball away. How does the force of the tennis racket affect the motion of the ball
defon

The force of the racket affects the ball's motion because it changes the momentum of the ball.

<h3>Impulse received by the ball</h3>

The impulse received by the ball through the racket affects the motion because it changes the momentum of the ball.

The ball which is initially at rest, will gain momentum after been hit with the racket.

J = ΔP = Ft

where;

  • J is the impulse received by the ball
  • ΔP is change in momentum of the ball
  • F is the applied force
  • t is the time of action

Thus, the force of the racket affects the ball's motion because it changes the momentum of the ball.

Learn more about impulse here: brainly.com/question/25700778

4 0
2 years ago
A 5-g lead bullet traveling in 20°C air at 300 m/s strikes a flat steel plate and stops.
densk [106]

To solve this problem it is necessary to apply the concepts related to the Kinetic Energy and the Energy Produced by the heat loss. In mathematical terms kinetic energy can be described as:

KE = \frac{1}{2} mv^2

Where,

m = Mass

v = Velocity

Replacing we have that the Total Kinetic Energy is

KE = \frac{1}{2} mv^2

KE = \frac{1}{2} (5*10^{-3})(300)^2

KE =  225J

On the other hand the required Energy to heat up t melting point is

Q_1 = mC_p \Delta T

Q_2 = L_f m

Where,

m = Mass

C_p =Specific Heat

\Delta T =Change at temperature

L_f = Latent heat of fussion

Heat required to heat up to melting point,

Q = Q_1+Q_2

Q = mC_p \Delta T+L_f m

Q = 5*0.128*(327-20) + 5*24.7

Q = 310J

The energy required to melt is larger than the kinetic energy. Therefore the heat of fusion of lead would be 327 ° C: The melting point of lead.

4 0
3 years ago
What are the characters associated with light as a wave​
Liono4ka [1.6K]

Answer:

Interference of light

Diffraction of light

Polarization of light

Reflection of light

all show the wave nature of light.

6 0
3 years ago
1 point
Yuliya22 [10]
PE= 3kg x 10N/kg x 10m
= 300J
8 0
3 years ago
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