Answer:
521 nm
Explanation:
Given the values and units we are given, I'm assuming 5.76*10^14 Hz is frequency.
The formula to use here is λ * υ = c, where λ is wavelength, υ is frequency, and c is the speed of light.
λ = ![\frac{3*10^8\frac{m}{s} }{5.76*10^{14}Hz} = {5.20833*10^{-7} m}\approx{521 *10^{-9}m}={521 nm}](https://tex.z-dn.net/?f=%5Cfrac%7B3%2A10%5E8%5Cfrac%7Bm%7D%7Bs%7D%20%7D%7B5.76%2A10%5E%7B14%7DHz%7D%20%3D%20%7B5.20833%2A10%5E%7B-7%7D%20m%7D%5Capprox%7B521%20%2A10%5E%7B-9%7Dm%7D%3D%7B521%20nm%7D)
Answer:
Part a)
V = 18.16 V
Part b)
![P_r = 345 Watt](https://tex.z-dn.net/?f=P_r%20%3D%20345%20Watt)
Part c)
P = 672 Watt
Part d)
V = 5.84 V
Part e)
![P_r = 345 Watt](https://tex.z-dn.net/?f=P_r%20%3D%20345%20Watt)
Explanation:
Part a)
When battery is in charging mode
then the potential difference at the terminal of the cell is more than its EMF and it is given as
![\Delta V = E + i r](https://tex.z-dn.net/?f=%5CDelta%20V%20%3D%20E%20%2B%20i%20r)
here we have
![E = 12 V](https://tex.z-dn.net/?f=E%20%3D%2012%20V)
![i = 56 A](https://tex.z-dn.net/?f=i%20%3D%2056%20A)
![r = 0.11](https://tex.z-dn.net/?f=r%20%3D%200.11)
now we have
![\Delta V = 12 + (0.11)(56) = 18.16 V](https://tex.z-dn.net/?f=%5CDelta%20V%20%3D%2012%20%2B%20%280.11%29%2856%29%20%3D%2018.16%20V)
Part b)
Rate of energy dissipation inside the battery is the energy across internal resistance
so it is given as
![P_r = i^2 r](https://tex.z-dn.net/?f=P_r%20%3D%20i%5E2%20r)
![P_r = 56^2 (0.11)](https://tex.z-dn.net/?f=P_r%20%3D%2056%5E2%20%280.11%29)
![P_r = 345 W](https://tex.z-dn.net/?f=P_r%20%3D%20345%20W)
Part c)
Rate of energy conversion into EMF is given as
![P_{emf} = i E](https://tex.z-dn.net/?f=P_%7Bemf%7D%20%3D%20i%20E)
![P_{emf} = (56)(12)](https://tex.z-dn.net/?f=P_%7Bemf%7D%20%3D%20%2856%29%2812%29)
![P_{emf} = 672 Watt](https://tex.z-dn.net/?f=P_%7Bemf%7D%20%3D%20672%20Watt)
Now battery is giving current to other circuit so now it is discharging
now we have
Part d)
![V = E - i r](https://tex.z-dn.net/?f=V%20%3D%20E%20-%20i%20r)
![V = 12 - (56)(0.11)](https://tex.z-dn.net/?f=V%20%3D%2012%20-%20%2856%29%280.11%29)
![V = 12 - 6.16 = 5.84 V](https://tex.z-dn.net/?f=V%20%3D%2012%20-%206.16%20%3D%205.84%20V)
Part e)
now the rate of energy dissipation is given as
![P_r = i^2 r](https://tex.z-dn.net/?f=P_r%20%3D%20i%5E2%20r)
![P_r = 56^2 (0.11)](https://tex.z-dn.net/?f=P_r%20%3D%2056%5E2%20%280.11%29)
![P_r = 345 W](https://tex.z-dn.net/?f=P_r%20%3D%20345%20W)
D is the best answer. In many physics problems we treat an extended object as if it were a point with the same mass located at the center of mass.
Answer:
bro i think ur from the uni of arid agriculture rawalpindi and today is your networking paper
Explanation:
Find the number of hours by dividing the distance by mph. The number of hours will be to the left of the decimal point:
250 miles / 65 mph
= 3.846153846
= 3 hours
2) Find the number of minutes by multiplying what is remaining from step 1 by 60 minutes. The minutes will be to the left of the decimal point:
0.846153846 x 60
= 50.76923076
= 50 minutes
3) Find the number of seconds by multiplying what is remaining from step 2 by 60 seconds. The seconds will be to the left of the decimal point:
0.76923076 x 60
= 46.1538456
= 46 seconds
So 3 hours 50 mins and 46 seconds