The answer to this question depends upon Newton's third law of motion. For every action, there's an equal and opposite reaction. Because of this law, during the collision between two unequal masses, the impulse that each mass receives will be of equal magnitude and and opposite sign.

8 0

2 years ago

While Robert was helping his father in the garden, he pushed a shovel into the ground to dig a hole in the dirt. He picked up a

makvit [3.9K]

Work done is given by the change in kinetic energy of an object

The kinetic energy of the shovel, the shrub, and in Robert's movement were changed, therefore, work is done in the given processes,

Reason:

Work is done when the total energy of object is affected by the application of force on the object over a distance

Therefore;

In option A, pushing the shovel into ground (to dig out the dirt) the requires the application of a force (push) over a distance, (into and out of the ground) therefore work is done

In option B, picking the shrub up gives it gravitational potential energy, therefore, work is done

In option C, carrying the shrub to the hole does visible work

In option D, holding the shrub while lowering it into the hole does work by preventing the shrub from falling randomly

Therefore, work is done in the given processes

Learn more about work-energy theorem here:

brainly.com/question/10063455

7 0

2 years ago

Consider a disk of radius 2.6 cm with a uni- formly distributed charge of +6.7.1C. Compute the magnitude of the electric field a

MrRissso [65]

Answer:

E=15.3*10¹³ N/C : approximate

Explanation:

We use the following formula to calculate the electric field due to a disk with uniform surface charge at a point P that is along the central perpendicular axis of the disk and at a distance x from the center of the disk:

E= 2*π*k*σ*F Fórmula ( 1 )

$F= 1-\frac{x}{\sqrt{R^{2}+x^{2} } }$

E: Electric field at point P (N/C)

σ: surface charge density (C/m²)

R: disk radio (m)

x :distance from the center of the disk to the point P located on the axis of the disk (m)

K: Coulomb constant ( N*m²/C)

Equivalences

1cm = 10⁻²m

1mm = 10⁻³m

Data

R =2.6 cm= 2.6*10⁻²m = 0.026m

x=3.7 mm = 3.7* 10⁻³m = 0,0037 m

Q=+6.71C.

k= 8.98774 * 10⁹ N* m²/C

Calculation of surface charge density (σ )

σ= Q/A

Q: uniformly distributed charge (C)

A: disk area (m²) = π*R²

σ= +6.71C/π*(2.6*10⁻²)²m² = 3159.56C/m²

Calculation of the electric field at point P

We apply formula (1) and replace data

E= 2*π*3159.56*8.98774*10⁹ *F

$F= 1-\frac{x}{\sqrt{R^{2}+x^{2} } }$

E=15.3*10¹³ N/C : approximate

3 0

2 years ago

Differentiate elastic potential energy and chemical potential energy

lorasvet [3.4K]

Answer: Elastic energy is the energy store in a.. compacted spring; an extended elastic band; and a drawn bow.

Chemical potential energy is position of electrons in specific substance bonds that can be broken (energizes).

7 0

2 years ago

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