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3 years ago

S=2n+2u solve for n.

Mathematics

2 answers:

Elena L [17]3 years ago

5 0

Answer:

n=(S/2)-u

Step-by-step explanation:

First, let's isolate 2n.

S-2u=2n

Let's divide both sides by 2.

(S/2)-u=n

n=(S/2)-u

Elza [17]3 years ago

3 0

Answer:

n= S/2 -vu

Step-by-step explanation:

S=2n+2u
2n= S- 2u
n= (S- 2u)/2
n= S/2 - u

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stealth61 [152]

Answer:

$\frac{{y}^{2}+13y-6}{{(y-1)}^{2}(y+7)}$

Step-by-step explanation:

1) Rewrite ${y}^{2}-2y+1y$ in the form ${a}^{2}-2ab+{b}^{2}$ , where a = y and b = 1.

$\frac{y}{{y}^{2}-2(y)(1)+{1}^{2}}+\frac{6}{{y}^{2}+6y-7}$

2) Use Square of Difference: ${(a-b)}^{2}={a}^{2}-2ab+{b}^{2}$ .

$\frac{y}{{(y-1)}^{2}}+\frac{6}{{y}^{2}+6y-7}$

3) Factor ${y}^{2}+6y-7$ .

1 - Ask: Which two numbers add up to 6 and multiply to -7?

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2 - Rewrite the expression using the above.

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Outcome/Result: $\frac{y}{(y-1)^2} +\frac{6}{(y-1)(y+7)}$

4) Rewrite the expression with a common denominator.

$\frac{y(y+7)+6(y-1)}{{(y-1)}^{2}(y+7)}$

5) Expand.

$\frac{{y}^{2}+7y+6y-6}{{(y-1)}^{2}(y+7)}$

6) Collect like terms.

$\frac{{y}^{2}+(7y+6y)-6}{{(y-1)}^{2}(y+7)}$

7) Simplify ${y}^{2}+(7y+6y)-6y$ to ${y}^{2}+13y-6y$

$\frac{{y}^{2}+13y-6}{{(y-1)}^{2}(y+7)}$

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2 years ago

Read 2 more answers

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Nady [450]

Answer:

Step-by-step explanation:

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1 year ago

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3 years ago

Find the area of the following shape, given its curves are made from parts of circles with diameters indicated on the diagram.

Alexxandr [17]

Answer:

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Step-by-step explanation:

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2 years ago

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