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grigory [225]
3 years ago
15

The difference between the sum of the masses of the electrons, protons and neutrons of an atom (calculated mass) and the actual

measured mass of the atom is called the a. nuclear mass b. isotopic mass c. decay mass d. critical mass e m ods ste e ova bas owrog gniuoo lest e. mass deficiency
Chemistry
1 answer:
sleet_krkn [62]3 years ago
6 0

Answer:

e. mass deficiency

Explanation:

The difference in the nuclei which is composed of the protons and the neutrons and the sum of the mass of the protons and the neutrons is called mass deficiency.

The definition of the mass deficiency can be applied to the whole atom.

The mass difference is equal to released binding energy.

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Limiting Reactants—————-
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21.8 grams.

Explanation:

Molar mass data from a modern periodic table:

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\displaystyle n = \frac{m}{M} = \frac{16.3}{24.301} = 0.670644\;\text{mol}.

The ratio between the coefficient of Mg and that of MgO is 2:2. Two moles of Mg will make two moles of MgO. 0.670644 moles of MgO will be produced if Mg is the limiting reactant.

How many moles of MgO will be produced if O₂ is the limiting reactant?

Number of moles of O₂:

\displaystyle n = \frac{m}{M} = \frac{4.33}{15.999} = 0.270642\;\text{mol}.

The ratio between the coefficient of O₂ and that of MgO is 1:2. One mole of O₂ will make two moles of MgO. 2\times 0.270642 = 0.541284\;\text{mol} of MgO will be produced if O₂ is in excess.

How many moles of MgO will be produced?

0.541284 is smaller than 0.670644. Only 0.541284 moles of MgO will be produced since O₂ will run out before all 16.3 grams of Mg is consumed.

What's the mass of 0.541284 moles of MgO?

Formula mass of MgO:

24.301 + 15.999 = 40.300\;\text{g}\cdot\text{mol}^{-1}.

Mass of 0.541284 moles of MgO:

m = n \cdot M = 0.541284\times 40.300 = 21.8\;\text{g}.

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