Answer:
The heat of vaporisation of methanol is "3.48 KJ/Mol"
Explanation:
The amount of heat energy required to convert or transform 1 gram of liquid to vapour is called heat of vaporisation
When 8.7 KJ of heat energy is required to vaporize 2.5 mol of liquid methanol.
Hence, for 1 mol of liquid methanol, amount of heat energy required to evaporate the methanol is = 
= 3.48 KJ
So, the heat of vaporization 
Therefore, the heat of vaporization of methanol is 3.48KJ/Mol
Answer: 1. P1V1 = P2V2
2. P stands for pressure
3. Units for Pressure are atm and Pa
4. V stands for volume
5. Units for volume is in mL
Explanation: Boyle's Law is a gas law that states the relationship between pressure and volume of a gas.
it has 5 electrons in it's outermost shell.
s 2e- , p 5e-
Answer:
Electrons are transferred between atoms together in the ionic compound. The ions are arranged in a regular repeating pattern in an ionic crystal
Explanation: